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krek1111 [17]
4 years ago
6

A sprinter accelerates from the starting block to a speed of 8.0 m/s in 4.0 s. What is the magnitude of the sprinter’s accelerat

ion?
A. 12.0 m/s

B. 2.0 m/s2

C. 2.0 m/s

D. 12.0 m/s2
Chemistry
2 answers:
Gwar [14]4 years ago
8 0

Answer:

The correct answer is B.

Explanation:

First, we must identify the data of the problem:

V_{0}: Initial speed.

V: Final speed.

a: Acceleration.

t: Time.

Using the cinematic formula:

V = V_{0} + a * t

We cleared the incognita a:

a = \frac{V - V_{0} }{t}

Since the sprinter starts from rest, we consider V_{0} = 0 \frac{m}{s}.

So when we replace the data in the equation we are left:

a = \frac{8 \frac{m}{s} - 0 \frac{m}{s}  }{4 s}

a= 2 \frac{m}{s^{2} }

Have a nice day!

Aneli [31]4 years ago
7 0

The acceleration is defined as the ratio between the change in speed and the change in time (i.e. the time elapsed to perform the speed change).

In this case, the reference to the "starting block" hints that the initial speed is 0, and the final speed is 8 m/s. This means that the change in speed is 8-0=8 m/s.

We are given that this change in speed takes place in 4 seconds.

So, the acceleration is the ratio between the change in speed and the time elapsed: 8/4=2m/s^2

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Answer:

The answer to your question is 510.7 kJ

Explanation:

Data

Q = ?

Volume = 2 L

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There are 3.0 g of NO and 3.0 g of CO reacting. what is the limiting reactant ?
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Answer:

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Explanation:

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By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

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The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

To determine the limiting reagent, you can use a simple rule of three as follows: If 56 grams of CO react with 60 grams of NO, 3 grams of CO react with how much mass of NO?

mass of NO=\frac{3 grams of CO*60 grams of NO}{56 grams of CO}

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<u><em></em></u>

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