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Mazyrski [523]
3 years ago
11

A hollow conductor is positively charged. A small uncharged metal ball is lowered by a silk thread (insulating material) through

a small opening in the top of the conductor and allowed to touch its inner surface. After the ball is removed, it will have: A. A positive charge B. A negative charge C. A charge whose sign depends on where the small hole is located in the conductor D. A charge whose sign depends on what part of the inner surface it touched E. No appreciable charge
Chemistry
1 answer:
laiz [17]3 years ago
4 0

Answer: Option (E) is the correct answer.

Explanation:

Since, the conductor is hollow which means that it is opened on both the ends. Hence, when a small uncharged metal ball is passed through it with the help of a silk thread then due to the presence of this insulating thread the ball will not come directly in contact with the charged rod.

As a result, there will occur no formation of opposite charge on the metal ball. Therefore, the ball will remain uncharged in nature.

Thus, we can conclude that after the given ball is removed, it will have no appreciable charge.

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Explanation:

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For example for the given equilibrium reaction;

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3 years ago
Chemistry help please! I just need to make sure the answers correct.... Thank you!
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1. At constant tempaerature and pressure, 3 tablets produce 600cm^3 of gas
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2. We have the equation PV = nRT, n being the number of moles
Pressure P = 1,000 kPa
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The Heliocentric model is when the sun, planets, and stars are orbiting a stationary Earth.
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2 years ago
24g of methane were burned in an excess of air. What mass of water would be produced in the reaction assuming complete combustio
expeople1 [14]

Answer:

54g of water

Explanation:

Based on the reaction, 1 mole of methane produce 2 moles of water.

To solve this question we must find the molar mass of methane in order to find the moles of methane added. With the moles of methane and the chemical equation we can find the moles of water produced and its mass:

<em>Molar mass CH₄:</em>

1C = 12g/mol*1

4H = 1g/mol*4

12g/mol + 4g/mol = 16g/mol

<em>Moles methane: </em>

24g CH₄ * (1mol / 16g) = 1.5 moles methane

<em>Moles water:</em>

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<em>Molar mass water:</em>

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<em>Mass water:</em>

3.0moles H₂O * (18g / mol) =

<h3>54g of water</h3>
8 0
3 years ago
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