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Mazyrski [523]
3 years ago
11

A hollow conductor is positively charged. A small uncharged metal ball is lowered by a silk thread (insulating material) through

a small opening in the top of the conductor and allowed to touch its inner surface. After the ball is removed, it will have: A. A positive charge B. A negative charge C. A charge whose sign depends on where the small hole is located in the conductor D. A charge whose sign depends on what part of the inner surface it touched E. No appreciable charge
Chemistry
1 answer:
laiz [17]3 years ago
4 0

Answer: Option (E) is the correct answer.

Explanation:

Since, the conductor is hollow which means that it is opened on both the ends. Hence, when a small uncharged metal ball is passed through it with the help of a silk thread then due to the presence of this insulating thread the ball will not come directly in contact with the charged rod.

As a result, there will occur no formation of opposite charge on the metal ball. Therefore, the ball will remain uncharged in nature.

Thus, we can conclude that after the given ball is removed, it will have no appreciable charge.

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A strip of sodium metal is bombarded by violet light (wavelength = 410 nm) at a rate of 10,000 photons per second, which causes
Zarrin [17]

Answer:

The minimum energy required to eject an electron from sodium will be bigger.

Explanation:

red light has a higher wavelength, that mean that the energy that emitted is lower in comparison with the violet light.

If the rate of the photons is the same, 10,000 photons per second, that  means that the required energy to take an electron need to be bigger to have the same effect.

Hope this info is useful.

3 0
3 years ago
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Nitric acid and nitrogen monoxide react to form nitrogen dioxide and water, like this: At a certain temperature, a chemist finds
poizon [28]

Answer:

K = 3.3

Explanation:

Nitric acid, HNO3, reacts with nitrogen monoxide, NO, to produce nitrogen dioxide, NO2 and water H2O as follows:

2HNO3(g) + NO(g) → 3NO2(g) + H2O(g)

Where equilibrium constant, K, is:

K = [NO2]³[H2O] / [HNO3]²[NO]

<em>[] is the molar concentration of each species at equilibrium.</em>

To solve this question we need to find molarity of each gas and replace these in the equation as follows:

<em>[NO2] -Molar mass NO2-46.0g/mol-</em>

18.6g * (1mol/46.0g) = 0.404mol / 7.7L = 0.0525M

<em>[H2O] -Molar mass:18.01g/mol- </em>

236.7g * (1mol/18.01g) = 13.14 moles / 7.7L = 1.707M

<em>[HNO3] -Molar mass:53.01g/mol-</em>

16.2g * (1mol/53.01g) = 0.3056 moles / 7.7L = 0.0397M

<em>[NO] -Molar mass: 30.0g/mol-</em>

11.0g * (1mol/30.0g) = 0.367 moles / 7.7L = 0.0476M

Replacing:

K = [NO2]³[H2O] / [HNO3]²[NO]

K = [0.0525M]³[1.707M] / [0.0397M]²[0.0476M]

<h3>K = 3.3</h3>

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4 0
3 years ago
How many molecules are there in 8.00 grams of glucose, C6H12O6
beks73 [17]

Answer:

molecules C6H12O6 = 2.674 E22 molecules.

Explanation:

from periodic table:

⇒ molecular mass C6H12O6 = ((6)(12.011)) + ((12)(1.008)) + ((6)(15.999))

⇒ Mw C6H12O6 = 180.156 g/mol

⇒ mol C6H12O6 = (8.00 g)(mol/180.156 g) = 0.0444 mol C6H12O6

∴ mol ≡ 6.022 E23 molecules

⇒ molecules C6H12O6 = (0.0444 mol)(6.022 E23 molecules/mol)

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6 0
3 years ago
When a pure sample of KNO3(s) spontaneously dissolves in water at room temperature, the solution becomes quite cold to the touch
jekas [21]

The enthalpy of the solution is <u>positive </u>and the entropy is <u>positive</u>.

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In its aqueous solution state, the randomness of molecules increases as a result of that the entropy will also increase leading to the positive state of the entropy.

Similarly, provided that the solution becomes quite cold to the touch, the enthalpy is also in it positive state.

Therefore, we can conclude that the enthalpy of the solution is <u>positive </u>and the entropy is <u>positive</u>.

Learn more about Potassium trioxonitrate (V) KNO₃(s) here:

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4 0
2 years ago
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3 years ago
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