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AVprozaik [17]
3 years ago
15

Show that the energy of a magnetic dipole m in a magnetic field B is U--m B

Physics
1 answer:
Juli2301 [7.4K]3 years ago
5 0

Answer:

showm

Explanation:

Consider a dipole having magnetic moment 'm' is placed in magnetic field \vec{B} then the torque exerted by the field on the dipole is

\tau = m\times B

\tau=mBsin\alpha

Now to rotate the dipole in the field to its final position the work required to be done is

U=\int \tau d\alpha

U=\int mBsin\alpha d\alpha

U= -mBcos\alpha

U=-\vec{m\times \vec{B}}

Minimum energy mB is for the case when m is anti parallel to B.

Minimum energy -mB is for the case when m is parallel to B.

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At the Earth's surface, a projectile is launched straight up at a speed of 10.0km / s. To what height will it rise? Ignore air r
icang [17]

At h = 5199.28 km  it will rise. Kinetic energy is a type of energy that is present in a particle or object in motion.

<h3>What is kinetic energy?</h3>

Kinetic energy is a type of energy that is present in a particle or object in motion. When work, which entails the transfer of energy, is done on an object by applying a net force, that object acquires kinetic energy.

There are five types of kinetic energy: mechanical, electrical, acoustic, thermal, and radiant. Kinetic energy (KE), which is the energy of a body in motion, is essentially the energy of all moving objects. It is one of the two main types of energy together with potential energy, which is the stored energy existing in objects at rest. 

<h3>To what height will it rise?</h3>

Equating the initial kinetic energy to the final potential energy

At the highest point, the body has only potential energy

initial kinetic energy = .5 * m * v2

velocity = 10.1 km/s

= 10.1 * 10100 m/s

= 10100 m/s

KE = .5 * m * (10100)2 = 51.005 x 106 x m   J

potential energy = m x g x h

max height reached = m x 9.81 x h

m x 9.81 x h =  51.005 x 106 x m   J

h = 5199.28 km

To learn more about kinetic energy, refer to:

brainly.com/question/25959744

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6 0
1 year ago
Help 30 points and willgive brainliest
MissTica
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3 years ago
II) A 0.40-kg ball, attached to the end of a horizontal ord, is rotated in a circle of radius 1.3 m on a friction- less horizont
Lostsunrise [7]

Hi there!

In this instance, the object spinning in a horizontal circle will experience a net force in the horizontal direction due to tension.

The net force is equivalent to the centripetal force, so:

∑F = T

mv²/r = T

Solve for v:

v = √rT/m

v = 13.96 m/s

3 0
2 years ago
if a 10kg object is lifted a distance of 10m from the rest what was the final velocity of the object?
Anastasy [175]
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3 years ago
A person weighs 60 kg. The area under the foot of the person is 150 cm2. Find the pressure exerted on the ground by the person.
9966 [12]

Answer:

40000 N/m²

Explanation:

Applying,

P =  F/A................... Equation 1

Where P = Pressure, F = Force, A = Area.

From the question,

The force(F) exerted by the person's foot is thesame as it's weight.

F = W = mg............ Equation 2

Where m = mass of the person, g = acceleration due to gravity.

Substitute equation 2 into equation 1

P = mg/A................ Equation 3

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Substitute these values into equation 3

P = (60×10)/0.015

P = 600/0.015

P = 40000 N/m²

3 0
3 years ago
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