Answer:
0.3 N
Explanation:
i = 400 A
B = 30 x 10^-6 T
L = 25 m
Force due the current carrying conductor placed in a magnetic field
F = B i L SinФ
where, Ф be the angle between length vector and magnetic field vector
F = 30 x 10^-6 x 400 x 25 = 0.3 N
Answer:
0.55 m/s
Explanation:
Parameters given:
Mass of lighter car, m = 1400 kg
Mass of heavier car, M = 1850 kg
Initial speed of lighter car, u = -1.10 m/s (since it's moving to the left)
Initial speed of heavier car, U = 1.5 m/s
Final sped of heavier car, V = 0.25 m/s
Using the principle of conservation of momentum, total initial momentum is equal to total final momentum:
m*u + M*U = m*v + M*V
Inputting the values:
(1400 * -1.1) + (1850 * 1.5) = (1400 * v) + (1850 * 0.25)
-1540 + 2775 = 1400v + 462.5
1235 = 1400v + 462.5
1400v = 772.5
v = 772.5/1400
v = 0.55 m/s
Maybe this works by asking more then you can finallly find what you looking for
Answer:
18N
Explanation:
Mechanical Advantage of crowbar (lever), MA = Length of effort arm / Length of resistance arm
Therefore, MA = 28 cm / 4.2 cm = 6.667
Force required to pull the nail, F = Friction force / MA
ie, F = 120 N / 6.667 = 18 N