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soldier1979 [14.2K]
3 years ago
13

An unknown element X has the following isotopes: ⁵²X (89.00% abundant), ⁴⁹X (8.00% abundant), ⁵⁰X (3.00% abundant). What is the

approximate atomic mass of X?
Chemistry
1 answer:
Vlad [161]3 years ago
6 0

Answer:

52 amu

Explanation:

To get the relative atomic mass of the element, we need to take into consideration, the atomic masses of the different isotopes and their relative abundances. We simply multiply the percentages with the masses. This can be obtained as follows:

[89/100 * 52] + [8/100 * 49] + [3/100 * 50]

46.28 + 3.92 + 1.5 =51.7 amu

The approximate atomic mass of element x is 52 amu

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4.<br> Think and discuss: Why is there an attraction between the two ions in this chemical bond?
Iteru [2.4K]

Answer:

One atom will give electrons to another atom to fill its shell, this is an ionic bond. The atom giving away electrons becomes positive and the one recieving electrons becomes negative.

Hope this helps

Explanation:

8 0
3 years ago
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mina [271]
I need more information, there are meant to be coefficients in front of one of those ..

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6 0
3 years ago
Ethers are almost always used as solvents for Grignard reactions, all of the reasons why they work so well are not fully underst
vfiekz [6]

Answer:

Ether is used as a solvent because it is aprotic and can solvate the magnesium ion.

Explanation:

Solubility in Water

Because ethers are polar, they are more soluble in water than alkanes of a similar molecular weight. The slight solubility of ethers in water results from hydrogen bonds between the hydrogen atoms of water molecules and the lone pair electrons of the oxygen atom of ether molecules.

Ethers as Solvents

Ethers such as diethyl ether dissolve a wide range of polar and nonpolar organic compounds. Nonpolar compounds are generally more soluble in diethyl ether than alcohols because ethers do not have a hydrogen bonding network that must be broken up to dissolve the solute. Because diethyl ether has a moderate dipole moment, polar substances dissolve readily in it.

Ethers are aprotic. Thus, basic substances, such as Grignard reagents, can be prepared in diethyl ether or tetrahydrofuran. These ethers solvate the magnesium ion, which is coordinated to the lone pair electrons of diethyl ether or THF. Figure attached, shows the solvation of a Grignard reagent with dietheyl ether.

The lone pair electrons of an ether also stabilize electron deficient species such as BF3 and borane (BH3). For example, the borane-THF complex is used in the hydroboration of alkenes (Section 1

5 0
4 years ago
You have an atom represented by X (not real by the way). X has 2 valence electrons. You have another atom Y that has 5 valence e
BabaBlast [244]

The chemical formula : X₃Y₂

<h3>Further explanation  </h3>

The noble gas element is a stable class of elements. The noble gas element is monatomic. Stability of noble gases is caused by an electron configuration that has a stable configuration of 8 (has 8 valence electrons) except He with a duplet configuration (has 2 valence electrons)

Other elements that do not yet have electron configurations such as noble gases will try to achieve their stability by forming bonds between elements.

This is generally called the octet rule

X has 2 valence electrons.to achieve stability, element X will release 2 electrons to form X²⁺

Y has 5 valence electrons, to achieve stability, the element Y will attract/ add electrons to form Y³⁻

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6 0
4 years ago
Find and fix each mistake in the following equilibrium constant expressions.
IRINA_888 [86]

Answer:

A. c. Keq=[H2]^2[S2]/[H2S]^2

B. b. Keq=[COCl2]/[CO][Cl2]

Explanation:

Hello,

In this case, considering the law of mass action which states that the equilibrium expression is written in terms of the concentration of products divided by the concentration of reactants considering the stoichiometric coefficients as powers we obtain:

A. For the reaction:

2H_2S(g)\rightleftharpoons 2H_2(g)+S_2(g)

The equilibrium expression is:

Keq=\frac{[H_2]^2[S_2]}{[H_2S]^2}

Therefore, answer is c. Keq=[H2]^2[S2]/[H2S]^2.

B. For the reaction:

CO(g)+Cl_2(g)\rightleftharpoons COCl_2(g)

The equilibrium expression is:

Keq=\frac{[COCl_2]}{[CO][Cl_2]}

Therefore, answer is b. Keq=[COCl2]/[CO][Cl2].

Regards.

8 0
3 years ago
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