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valentina_108 [34]
4 years ago
6

How many grams of AgNo3 are required to make 25 ml of .80M solution

Chemistry
1 answer:
Aleks [24]4 years ago
8 0

Answer:

<u>3.39 grams </u>of AgNo3 are required to make 25 ml of .80M solution

Explanation:

Molarity , M = 0.80

Volume = 25 ml

=\frac{25}{1000} L

V = 0.025 L

molarity = \frac{moles}{Volume\ of\ solution(L)}

M=\frac{n}{V}

Here n = number of moles

n=M\times V

n=0.8\times 0.025

n = 0.02 mole

moles = \frac{given\ mass}{Molar\ mass}

Molar mass of AgNO3 = 169.87 g/mol

mass =\frac{n}{Molar\ mass}

mass=\frac{0.02}{169.87}

Mass = 3.397 g

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