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ra1l [238]
3 years ago
6

You have an atom represented by X (not real by the way). X has 2 valence electrons. You have another atom Y that has 5 valence e

lectrons.
What is the chemical formula when these two atoms combine with each other?
Chemistry
1 answer:
BabaBlast [244]3 years ago
6 0

The chemical formula : X₃Y₂

<h3>Further explanation  </h3>

The noble gas element is a stable class of elements. The noble gas element is monatomic. Stability of noble gases is caused by an electron configuration that has a stable configuration of 8 (has 8 valence electrons) except He with a duplet configuration (has 2 valence electrons)

Other elements that do not yet have electron configurations such as noble gases will try to achieve their stability by forming bonds between elements.

This is generally called the octet rule

X has 2 valence electrons.to achieve stability, element X will release 2 electrons to form X²⁺

Y has 5 valence electrons, to achieve stability, the element Y will attract/ add electrons to form Y³⁻

The two compounds will form a compound with the charges crossed : X₃Y₂

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If 5.57 g of Ag2O is sealed in a 75.0-mL tube filled with 760 torr of N2 gas at 28 ∘C, and the tube is heated to 310 ∘C, the Ag2
Snezhnost [94]

Answer: Total pressure = 7293.2 torr or 9.60 atm

Explanation:

<em>Total pressure = partial pressure of nitrogen + partial pressure of oxygen</em>

The partial pressure due to nitrogen is determined using the equation of Gay-Lussac's law: <em>P₁/T₁=P₂/T₂</em>

P₁ = 760 torr = 1atm, T₁ = 28∘C = (273+28)K = 301k, P₂ = ?, T₂ = 310∘C =(310+273)K = 583K

P₂ = P₁ T₂/ T₁

P₂ = 760 * 583 / 301 = 1472.03 torr

The pressure due to Oxygen gas produced is calculated thus:

Balanced equation of the decomposition of Ag₂O at s.t.p. is as follows;

2Ag₂O ----> 4Ag + O₂(g)

2 moles of Ag₂O produces 1 mole of O₂

molar mass of Ag₂O = (2*108 + 16)g = 232g/mol

molar volume of gas at s.t.p. = 22.4L

2*232g i.e. 464g of Ag₂O produces 22.4L of O₂

5.57g of Ag₂O will produce 5.57g*22.4L/464g = 0.269L or 269mL of O₂

Using the General gas equation  P₁V₁/T₁=P₂V₂/T₂

P₁ = 1atm = 760 torr, V₁ = 269mL, T₁=273K, P₂ = ?, V₂= 75mL, T₂ = 583K

P₂ = P₁V₁T₂/V₂T₁

P₂ = 760*269*583 / 75*273

P₂ = 5821.17 torr

Total pressure = (1472.03 + 5821.17) torr

Total pressure = 7293.2 torr or 9.60 atm

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3 years ago
There are 1.204 x 10^24 atoms of oxygen. How many moles is this?
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7.25 x 10^47

Explanation:

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