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Citrus2011 [14]
3 years ago
10

Human organ systems work together in many ways. Which statement accurately explains the relationship between two body systems?A.

the excretory system regulates the temperature of the integumentary system.B. The skeletal system delivers nutrients absorbed by the endocrine system.C. The digestive system delivers oxygen absorbed by the respiratory system.D. The nervous system regulates the movement of the muscular system.
Chemistry
1 answer:
melomori [17]3 years ago
4 0

Answer:

Option D. The nervous system regulates the movement of the muscular system.

Explanation:

The nervous system regulates the movement of the muscles as they receive signals from both the brain and nerve cells

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Considere la siguiente reacción: H, (g) +1, (a) = 2 HI (9). K, para la reacción es 54.3 a 430°C. Si se coloca H, 0.00623M, 0.004
bearhunter [10]

Answer:

[HI] = 0.0255M

[H₂] = 0.00466M

[I₂] = 0.00257M

Explanation:

Para la reacción:

H₂(g) + I₂(g) ⇄ 2HI(g)

La constante de equilibrio, K, se define como:

54.3 = [HI]² / [H₂] [I₂]

Donde cada concentración [] será la concentración en equilibrio para cada especie

Para saber la dirección del equilibrio definiremos Q como:

Q = [HI]² / [H₂] [I₂]

Donde las concentraciones [] serán las concentraciones actuales de cada gas

Reemplazando:

Q = [0.0224M]² / [0.00623M] [0.00414M]

Q = 19.5

Como Q<K, la reacción se desplazará hacia la derecha produciendo más [HI]. Así, las concentraciones en equilibrio serán:

[HI] = 0.0224M +2X

[H₂] = 0.00623M - X

[I₂] = 0.00414 - X

54.3 = [0.0224M +2X]² / [0.00623M - X] [0.00414M - X]

54.3 = 0.00050176 + 0.0896 X + 4 X² / 0.0000257922 - 0.01037 X + X²

0.00140052 - 0.563091 X + 54.3 X² =  0.00050176 + 0.0896 X + 4 X²

0.00089876 - 0.652691 X + 50.3 X² = 0

Resolviendo la ecuación cuadrática:

X = 0.001566M → Solución verdadera

X = 0.01141M → Falsa solución. Produciría concentraciones negativas

Reemplazando:

[HI] = 0.0224M +2*0.001566M

[H₂] = 0.00623M - 0.001566M

[I₂] = 0.00414 - 0.001566M

[HI] = 0.0255M

[H₂] = 0.00466M

[I₂] = 0.00257M

Siendo estas últimas, las concentraciones de las especies luego de alcanzar el equilibrio.

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