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otez555 [7]
3 years ago
12

An ebonite (very hard, black rubber) rod is rubbed with the four different substances below. Choose the one that is MOST likely

to produce the largest static charge by friction.
An ebonite (very hard, black rubber) rod is rubbed with the four different substances below. Choose the one that is MOST likely to produce the largest static charge by friction.
A) fur
B) paper
C) silk
D) wax
Chemistry
2 answers:
maksim [4K]3 years ago
6 0
D i think is right

or




Nataly [62]3 years ago
4 0
A. Fur will produce the largest static charge
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A 5.0 balloon containing nitrogen gas is cooled from 25 degrees to 5°C. What is the final volume of the balloon?
mylen [45]

Answer:

5.4

Explanation:

V1=5.0

T1=25+ 273=298

V2= z(unknown)

T2=5+273=278

V1/T1 =V2/T2

V2=V1T2/T1

=5*298/278

=5.4

5 0
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What belief do Deists hold about the universe?
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8 0
3 years ago
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A closed, frictionless piston-cylinder contains a gas mixture with the following composition on a mass basis: 40% carbon dioxide
Hitman42 [59]

Answer:

W=-37.6kJ, therefore, work is done on the system.

Explanation:

Hello,

In this case, the first step is to compute the moles of each gas present in the given mixture, by using the total mixture weight the mass compositions and their molar masses:

n_{CO_2}=0.8kg*0.4*\frac{1kmolCO_2}{44kgCO_2}= 0.00727kmolCO_2\\\\n_{O_2}=0.8kg*0.25*\frac{1kmolO_2}{32kgO_2}=0.00625kmolO_2\\ \\n_{Ne}=0.8kg*0.35*\frac{1kmolNe}{20.2kgNe}=0.0139kmolNe

Next, the total moles:

n_T=0.00727kmol+0.00625kmol+0.0139kmol=0.02742kmol

After that, since the process is isobaric, we can compute the work as:

W=P(V_2-V_1)

Therefore, we need to compute both the initial and final volumes which are at 260 °C and 95 °C respectively for the same moles and pressure (isobaric closed system)

V_1=\frac{n_TRT_1}{P}= \frac{0.02742kmol*8.314\frac{kPa*m^3}{kmol\times K}*(260+273)K}{450kPa}=0.27m^3\\ \\V_2=\frac{n_TRT_2}{P}= \frac{0.02742kmol*8.314\frac{kPa*m^3}{kmol\times K}*(95+273)K}{450kPa}=0.19m^3

Thereby, the magnitude and direction of work turn out:

W=450kPa(0.19m^3-0.27m^3)\\\\W=-37.6kJ

Thus, we conclude that since it is negative, work is done on the system (first law of thermodynamics).

Regards.

7 0
3 years ago
The form of heat transfer taking place in the crust of the earth would be ____
Anna [14]
The form of heat transfer taking place in the crust of the Earth would be Convection.
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A certain orbital of the hydrogen atom has n = 4 and l = 2 what are the possible values of ml for this orbital?
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