In most four-sroke internal combustion engines, when does the piston move downward?
2 answers:
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Answer:
Explanation:
given,
mass of wheel(M) = 3 Kg
radius(r) = 35 cm
revolution (ω_i)= 800 rev/s
mass (m)= 1.1 Kg
I_{wheel} = Mr²
when mass attached at the edge
I' = Mr² + mr²
using conservation of angular momentum
Answer:
231.98 mL
Explanation:
V₁ = Initial volume = 205 mL
V₂ = Final volume
P₁ = Initial pressure = 712 mmHg
P₂ = Final pressure = 750 mmhg (STP)
T₁ = Initial temperature = -44 °C = 229.15 K
T₂ = Final temperature = 273.15 K (STP)
From Combined gas law
Volume of the argon at STP is 231.98 mL
Answer: (2) Use the Momentum Principle.
Explanation:
In fact, it is called the <u>Conservation of linear momentum principle,</u> which establishes the initial momentum of the asteroids before the collision must be equal to the final momentum
after the collision, no matter if the collision was elastic or inelastic (in which the kinetic energy is not conserved).
In this sense, the linear momentum of a body is defined as:
Where is the mass and
the velocity.
Therefore, the useful approach in this situation is<u> option (2)</u>.