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Dennis_Churaev [7]
4 years ago
8

In most four-sroke internal combustion engines, when does the piston move downward?

Physics
2 answers:
horrorfan [7]4 years ago
8 0
After 2 nd cycle I m sure 100%
gregori [183]4 years ago
6 0
<span>During the power and intake strokes.</span>
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Select the correct answer. What is tan for the given triangle? 0.60 1.67 1.33 5.00 0.20
GuDViN [60]
The answer is 1.33 i hope this helps you
8 0
3 years ago
Read 2 more answers
A 3-kg wheel with a radius of 35 cm is spinning in the horizontal plane about a vertical axis through its center at 800 rev/s. A
Kruka [31]

Answer:

\omega_f = 585.37 \ rev/s

Explanation:

given,

mass of wheel(M) = 3 Kg

radius(r) = 35 cm

revolution (ω_i)=  800 rev/s

mass (m)= 1.1 Kg

I_{wheel} = Mr²

when mass attached at the edge

I' = Mr² + mr²

using conservation of angular momentum

I \omega_i = I' \omega_f

(Mr^2) \times 800 = ( M r^2 + m r^2) \omega_f

M\times 800 = ( M + m )\omega_f

3\times 800 = (3+1.1)\times \omega_f

2400 = (4.1)\times \omega_f

\omega_f = 585.37 \ rev/s

3 0
4 years ago
A sample of argon has a volume of 205 mL when its temperature is -44.0 oC and its pressure is 712 mm of Hg. What would be the vo
anzhelika [568]

Answer:

231.98 mL

Explanation:

V₁ = Initial volume = 205 mL

V₂ = Final volume

P₁ = Initial pressure = 712 mmHg

P₂ = Final pressure = 750 mmhg (STP)

T₁ = Initial temperature = -44 °C = 229.15 K

T₂ = Final temperature = 273.15 K (STP)

From Combined gas law

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}\\\Rightarrow V_2=\frac{P_1V_1T_2}{T_1P_2}\\\Rightarrow V_2=\frac{712\times 205\times 273.15}{229.15\times 750}=231.98\ mL

Volume of the argon at STP is 231.98 mL

5 0
4 years ago
Read 2 more answers
Two asteroids in outer space collide, and stick together. The mass of each asteroid, and the velocity of each asteroid before th
Naddik [55]

Answer: (2) Use the Momentum Principle.

Explanation:

In fact, it is called the <u>Conservation of linear momentum principle,</u> which establishes the initial momentum p_{i} of the asteroids before the collision must be equal to the final momentum p_{f} after the collision, no matter if the collision was elastic or inelastic (in which the kinetic energy is not conserved).

In this sense, the linear momentum p of a body is defined as:

p=mV

Where m is the mass and V the velocity.

Therefore, the useful approach in this situation is<u> option (2)</u>.

7 0
3 years ago
Is bath oil a homologenous mixture?
DaniilM [7]
Examples: 
<span>Air </span>
<span>Blood </span>
<span>Mouthwash </span>
<span>Rubbing Alcohol </span>
<span>Peroxide </span>
<span>Hand-sanitizer </span>
<span>Perfume </span>
<span>Some bath gels </span>
<span>Coffee </span>
<span>Chicken or Beef Broth </span>
<span>Body Spray </span>
<span>Natural Oils </span>

<span>A heterogeneous mixture is a mixture where the components of the mixture are not uniform or have localized regions with different properties. </span>

<span>Examples: </span>
<span>Rocks </span>
<span>Oil and water </span>
<span>Soup </span>
<span>Pizza </span>
<span>Copper sulfate </span>
<span>Salsa </span>
<span>Chicken soup </span>
<span>Cottage cheese

hope that helped</span>
5 0
3 years ago
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