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raketka [301]
3 years ago
11

Select the correct answer. What is tan for the given triangle? 0.60 1.67 1.33 5.00 0.20

Physics
2 answers:
GuDViN [60]3 years ago
8 0
The answer is 1.33 i hope this helps you
Dmitry [639]3 years ago
8 0
The correct answer should be 1.33
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An airplane flies with a constant speed of 720 km/hr. How long will it take to travel a distance of 1440 km? Please show your wo
choli [55]

Answer:

2 h

Explanation:

Velocity =Distance/time ⇒ time = distance/speed

                                                     = 1440/720

                                                     = 2 h

6 0
3 years ago
BRAINLIEST AND MAY DOUBLE POINTS!!!
raketka [301]

Given that:

 Energy of bulb  (Work ) = 30 J,

 Time (t) = 3 sec

The power consumption =  ?

 We know that, Power can be defined as rate of doing work

              Power (P) = Work(Energy supplied) ÷ time

                               = 30 ÷ 3

                              = 10 Watts

<em> The power consumption is 10 W.</em>


3 0
3 years ago
What’s the most distant object in the solar system
Scrat [10]

Answer:

pluto

Explanation:

i had the same question

7 0
3 years ago
Read 2 more answers
A batter swings at a baseball. The action force is the bat hitting the ball with a force of 5N. The reaction force, however, can
dlinn [17]
This is false. The reaction force can be determined.
6 0
3 years ago
The outer layer of cable on a cable reel is 16.2 cm from the center of the reel. The reel is initially stationary and can rotate
ahrayia [7]

Answer:

B. w=12.68rad/s

C. α=3.52rad/s^2

Explanation:

B)

We can solve this problem by taking into account that (as in the uniformly accelerated motion)

\theta=\omega_{0}t+\frac{1}{2}\alpha t^{2}\\\theta = \frac{s}{r}      ( 1 )

where w0 is the initial angular speed, α is the angular acceleration, s is the arc length and r is the radius.

In this case s=3.7m, r=16.2cm=0.162m, t=3.6s and w0=0. Hence, by using the equations (1) we have

\theta=\frac{3.7m}{0.162m}=22.83rad

22.83rad=\frac{1}{2}\alpha (3.6s)^2\\\\\alpha=2\frac{(22.83rad)}{3.6^2s}=3.52\frac{rad}{s^2}

to calculate the angular speed w we can use\alpha=\frac{\omega _{f}-\omega _{i}}{t _{f}-t _{i}}\\\\\omega_{f}=\alpha t_{f}=(3.52\frac{rad}{s^2})(3.6)=12.68\frac{rad}{s}

Thus, wf=12.68rad/s

C) We can use our result in B)

\alpha=3.52\frac{rad}{s^2}

I hope this is useful for you

regards

3 0
3 years ago
Read 2 more answers
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