Answer:
A and D
Step-by-step explanation:
<span>a) Differentiate both sides of lnq − 3lnp + 0.003p=7 with respect to p, keeping in mind that q is a function of p and so using the Chain Rule to differentiate any functions of q:
(1/q)(dq/dp) − 3/p + 0.003 = 0
dq/dp = (3/p − 0.003)q.
So E(p) = dq/dp (p/q) = (3/p − 0.003)(q)(p/q) = (3/p − 0.003)p = 3 − 0.003p.
b) The revenue is pq.
Note that (d/dp) of pq = q + p dq/dp = q[1 + dq/dp (p/q)] = q(1 + E(p)), which is zero when E(p) = −1. Therefore, to maximize revenue, set E(p) = −1:
3 − 0.003p = −1
0.003p = 4
p = 4/0.003 = 4000/3 = 1333.33</span>
Answer:
I am not sure but I think it is 3
Step-by-step explanation:
2x+29=5x+20
5x-2x+29=20
3x=-9
1x=3
2x2-3x-20=0
4-3x-20=0
2-20=-16
-3x-16=0
-3x=16
x= -5.33333
I think i did it right. i hope this helps.
You seem to already see that you need to multiple x with the other numbers. When you start off solving it you'd get.. x-6=x2(to the power of) + 6x . Then just move the equation over from the left to the right. and solve, I've got -6+x2(power of 2)+7x, that's it
