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snow_tiger [21]
3 years ago
12

By how much does the earth-Sun distance change? 300,000 miles 500,000 miles 3,000,000 miles 3,500 miles

Physics
1 answer:
iogann1982 [59]3 years ago
4 0

Answer:

3,000,000 miles

Explanation:

The Earth's perihelion distance is about 147,000,000 kilometers and its aphelion distance is about 152,000,000 kilometers. So, the change in distance is about 5,000,000 kilometers which translates to about 3,000,000 in Miles.

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A car of mass 800 kg is travelling at 30 m/S. The car then brakes suddenly and stops with a braking distance of 75 m find the wo
gulaghasi [49]

Answer:

-360 kJ

Explanation:

Given:

m = 800 kg

v₀ = 30 m/s

v = 0 m/s

Δx = 75 m

Find: W

We can solve this using either forces or energy.

To use forces, first find the acceleration.

v² = v₀² + 2aΔx

(0 m/s)² = (30 m/s)² + 2a (75 m)

a = -6 m/s²

Then apply Newton's second law:

∑F = ma

F = (800 kg) (-6 m/s²)

F = -4800 N

Work is force times distance:

W = FΔx

W = (-4800 N) (75 m)

W = -360,000 J

W = -360 kJ

If you want to use energy instead:

work = change in energy

W = ΔKE

W = ½mv² − ½mv₀²

W = ½ (800 kg) (0 m/s)² − ½ (800 kg) (30 m/s)²

W = -360,000 J

W = -360 kJ

4 0
3 years ago
Fourth and fifth and what is come before latter e​
Romashka [77]

Answer:

d

Explanation:

3 0
3 years ago
A transverse wave is set up in a very long string. The oscillator is set at 20.0 Hz, and the wave speed is 78 m/s. The amplitude
Sedbober [7]

To solve this problem we must apply the concepts related to Tangential Acceleration based on angular velocity and acceleration, and therefore, we must also calculate angular velocity based on the given frequency. For all these problems we will take the Units to the International System. The maximum acceleration would then be defined as,

a_{max} = \omega^2 A

Here,

\omega= Angular velocity

A = Amplitude

At the same time the angular velocity is described as,

\omega = 2\pi f

Here f means the frequency of the wave. Substituting,

\omega = 2 \pi (20)

\omega = 40\pi

A = 5.2cm

A = 0.052m

Replacing at the first equation,

a_{max} = (40\pi )^2 (0.052)

a_{max} = 821.15m/s^2

Therefore the maximum particle acceleration for a point on the string is 821.15m/s^2

6 0
4 years ago
A light aircraft travels 2 miles per hour less than twice the speed of a van. If the van can travel 171 miles in the same time i
Gnom [1K]

Answer:

The answers to the question are as follows

The average speed of the aircraft = 112 miles/hr and

the average speed of the van= 57 miles/hr

Explanation:

Speed of the van = X

Speed of the aircraft  = Y = 2 × X - 2 miles/hour

Distance covered by van  in time t = 171 miles

Distance covered by aircraft in time t = 336 miles

Therefore Y × t = 336 miles and

X × t = 171 miles

Therefore (2·X -2) × t = 336 miles

and  t = (171 miles)/X

(2·X -2) × (171 miles)/X  = 336 miles

(342·X-342)/X =336 → 6·X = 342

Therefore X = 57 miles/hour

and Y =2×57 -2 = 112 miles/hr

8 0
3 years ago
What dictates how proteins are assembled in our body?
kari74 [83]
<h3><em>The body's main sources of energy are carbohydrate and fat. At times, protein can serve as an energy source in which the liver removes an amine group from the amino acid.</em></h3>
8 0
3 years ago
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