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aev [14]
3 years ago
6

Active transport requires energy in order to move molecules ____________ the concentration gradient while simple and facilitated

diffusion require no energy to move molecules __________ the concentration gradient.
Physics
1 answer:
S_A_V [24]3 years ago
4 0

Answer:

Active transport requires energy in order to move molecules <u>against</u> the concentration gradient while simple and facilitated diffusion require no energy to move molecules <u>down</u> the concentration gradient.

Explanation:

Active transport requires energy as the substance move from low concentration to high concentration (<u>substances move against concentration gradient</u>).

For example, Sodium-potassium pump.

Passive transport does not require energy as the substance move from high concentration to low concentration (<u>substances move only down their concentration gradient</u>).

It is of two types: Simple and facilitated transport.

For example, Osmosis.

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Which statement best describes the superposition principle?
Natasha_Volkova [10]
<h3><u>Answer;</u></h3>

A. If two in-phase waves arrive simultaneously at a point, their amplitudes add up.

<h3><u>Explanation;</u></h3>
  • <u>According to the principle of superposition, when two waves of the same kind meet at a point in space, the resultant displacement at that point is the vector sum of the displacements that the two waves would separately produce at that point.</u>
  • Interference involves the superposing of two or more coherent waves to produce regions of maxima and minima in space, according to the principle of superposition.
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4 years ago
2. Which energy sources (input) cause the solar panels to generate electrical energy?
Daniel [21]

Answer:

Explanation:

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7 0
4 years ago
A cubical box measuring 1.29 m on each side contains a monatomic ideal gas at a pressure of 2.0 atm How much thermal energy do t
Marrrta [24]

Answer:

a) U = 652.545\,kJ, b) v \approx 659.568\,\frac{m}{s}

Explanation:

a) According to the First Law of Thermodinamics, the system is not reporting any work, mass or heat interactions. Besides, let consider that such box is rigid and, therefore, heat contained inside is the consequence of internal energy.

Q = U

The internal energy for a monoatomic ideal gas is:

U = \frac{3}{2} \cdot n \cdot R_{u} \cdot T

Let assume that cubical box contains just one kilomole of monoatomic gas. Then, the temperature is determined from the Equation of State for Ideal Gases:

T = \frac{P\cdot V}{n\cdot R_{u}}

T = \frac{(202.65\,kPa)\cdot(1.29\,m)^{3}}{(1\,kmole)\cdot(8.314\,\frac{kPa\cdot m^{3}}{kmole\cdot K} )}

T = 52.325\,K

The thermal energy contained by the gas is:

U = \frac{3}{2}\cdot (1\,kmole)\cdot (8.314\,\frac{kPa\cdot m^{3}}{kmole\cdot K})\cdot (52.325\,K)

U = 652.545\,kJ

b) The physical model for the cat is constructed from Work-Energy Theorem:

U = \frac{1}{2}\cdot m_{cat} \cdot v^{2}

The speed of the cat is obtained by isolating the respective variable and the replacement of every known variable by numerical values:

v = \sqrt{\frac{2 \cdot U}{m_{cat}}}

v = \sqrt{\frac{2\cdot (652.545 \times 10^{3}\,J)}{3\,kg} }

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3 0
3 years ago
3. Consider a locomotive and the rest of a freight train to be a single object. Suppose the locomotive is pulling the train up a
34kurt

Answer:

The friction force and the x component for the weight should be the reaction forces that are opposite and equal to the action force, which causes the locomotive to move up the hill if the velocity of the locomotive remains constant.  

Explanation:

<u>When the locomotive starts to pull the train up, appears two reaction forces opposed to the action force in the direction of the move. </u>

The first one is due to the friction between the wheels and the ground, it will be the friction force (Fr):

Fr = μ*Pₓ =μmg*sin(φ)        

<em>where μ: friction dynamic coefficient, Pₓ: is the weight component in the x-axis, m: total mass = train's mass + locomotive's mass, g: gravity, and sin(φ): is the angle respect to the x-axis.</em>              

And the second one is the x component for the weight (Wₓ):

Wₓ = mg*cos(φ)  

<em>where cos(φ): is the angle respect to the y-axis.    </em>

<em> </em>

These two forces should be the same as the action force, which causes the locomotive to move up the hill if the velocity of the locomotive remains constant.          

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4 years ago
What is the formula to find initial velocity?​
Inga [223]

Answer:

s = ut + 1/2at^2

Explanation:

s= distance

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a= acceleration

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