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aev [14]
3 years ago
6

Active transport requires energy in order to move molecules ____________ the concentration gradient while simple and facilitated

diffusion require no energy to move molecules __________ the concentration gradient.
Physics
1 answer:
S_A_V [24]3 years ago
4 0

Answer:

Active transport requires energy in order to move molecules <u>against</u> the concentration gradient while simple and facilitated diffusion require no energy to move molecules <u>down</u> the concentration gradient.

Explanation:

Active transport requires energy as the substance move from low concentration to high concentration (<u>substances move against concentration gradient</u>).

For example, Sodium-potassium pump.

Passive transport does not require energy as the substance move from high concentration to low concentration (<u>substances move only down their concentration gradient</u>).

It is of two types: Simple and facilitated transport.

For example, Osmosis.

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Which type of electromagnetic wave often encodes information for sound?
AysviL [449]
I think the answer is D

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8 0
3 years ago
The plates of a parallel-plate capacitor are 2.50 mm apart, and each carries a charge of magnitude 77.0 nC. The plates are in va
WINSTONCH [101]

Answer:

Part A: 7500 V

Part B: 2.899×10⁻³ m²

Part C: 10.27 pF or 10.27×10⁻¹² F

Explanation:

Part A:

Applying,

E = V/d................ Equation 1

Where E = electric field intensity between the plates, V = potential difference between the plates, d = distance of separation between the plates

make V the subject of the equation above,

V = Ed............. Equation 2

Given: E = 3.0×10⁶ V/m, d = 2.5 mm = 2.5×10⁻³ m

Substitute into equation 2

V =  3.0×10⁶ (2.5×10⁻³ )

V = 7.5×10³ V

V = 7500 V

Part B:

Using,

E = Q/(e₀A).................... Equation 3

Where Q = Charge on each plate of the capacitor, A = Area of each plate, e₀ = constant = dielectric = permitivity of free space

make A the subject of the equation,

A = Q/(e₀E).............. Equation 4

Given: Q = 77 nC = 77×10⁻⁹ C, E = 3.0×10⁶ V/m

Constant: e₀ = 8.854×10⁻¹² F/m

Substitute into equation 4

A = 77×10⁻⁹/(8.854×10⁻¹²× 3.0×10⁶)

A = 77×10⁻⁹/(26.562×10⁻⁶)

A = 2.899×10⁻³ m²

A = 2.899×10⁻³ m².

Part C:

Using,

Q = CV.................. Equation 5

Where C = Capacitance of the capacitor

make C the subject of the equation

C = Q/V.............. Equation 6

Given: Q = 77 nC = 77×10⁻⁹ C, V = 7500 V

Substitute into equation 6

C = 77×10⁻⁹/7500

C = 10.27×10⁻¹² F

C = 10.27 pF

5 0
3 years ago
Sam heaves a 16-lb shot straight up, giving it a constant upward acceleration from rest of 35.0 m/s2 for 64.0 cm. He releases it
stich3 [128]

Answer:

a. 6.69m/s

b. y=4.48m

c. t=1.43secs

Explanation:

Data given, acceleration,a=35m/s^2

distance covered,d=64cm=0.64m,

a. to determine the speed, we use the equation of motion

initial velocity,u=0m/s

if we substitute values we arrive at

v^{2}=u^{2}+2as\\v^{2}=0+2*35*0.64\\v^{2}=44.8m/s\\v=\sqrt{44.8}\\ v=6.69m/s\\

b. After taking the shot,the acceleration value is due to gravity i.e a=9.81m/s^2

and the distance becomes (y-2.2) above the ground. When it reaches the maximum height, the final velocity becomes zero and the initial velocity becomes 6.69m/s.

Hence we can write the equation above again

v^{2}=u^{2}-2a(y-2.2)\\

if we substitute values we have

v^{2}=u^{2}-2a(y-2.2)\\0=6.69^{2}-2*9.81(y-2.2)\\y-2.2=\frac{44.76}{19.62} \\y=2.28+2.2\\y=4.48m

c. the time it takes to arrive at 1.83m is obtain by using the equation below

1.83-2.2=6.69t-\frac{1}{2} *9.81t^{2}\\4.9t^{2}-6.69t-0.37\\using \\t= \frac{-b±\sqrt{b^{2}-4ac} }{2a}\\ where \\a=4.9, b=-6.69, c=-0.37

if we insert the values, we solve for t , hence t=1.43secs

6 0
3 years ago
The acceleration of gravity on Mars is about 3.7 meters per second squared. Suppose a rock falls from a tall cliff on Mars. Writ
ratelena [41]

Answer:

The answer to your question is  Equation  vf = gt;  vf = 29.6 m/s

Explanation:

Data

gravity = 3.7 m/s²

vf = ?

time = t = 8 s

Formula

       vf = vo + gt

Initial speed = 0 m/s

To solve this problem we can use the equations of free fall and just substitute the data.

- Substitution

      vf = 0 + (3.7)(8)

- Simplification

      vf = 29.6 m/s

7 0
3 years ago
Is Particle B charged or uncharged? If charged, indicate whether it is charged positively or negatively. (n = neutron, p = proto
diamong [38]

Answer:

community College program and maddie d

Explanation:

work business work and maddie

7 0
3 years ago
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