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aev [14]
3 years ago
6

Active transport requires energy in order to move molecules ____________ the concentration gradient while simple and facilitated

diffusion require no energy to move molecules __________ the concentration gradient.
Physics
1 answer:
S_A_V [24]3 years ago
4 0

Answer:

Active transport requires energy in order to move molecules <u>against</u> the concentration gradient while simple and facilitated diffusion require no energy to move molecules <u>down</u> the concentration gradient.

Explanation:

Active transport requires energy as the substance move from low concentration to high concentration (<u>substances move against concentration gradient</u>).

For example, Sodium-potassium pump.

Passive transport does not require energy as the substance move from high concentration to low concentration (<u>substances move only down their concentration gradient</u>).

It is of two types: Simple and facilitated transport.

For example, Osmosis.

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now we will have the time to complete the rotation given as

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speed = \frac{distance}{time}

speed = \frac{\pi D}{t}

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v = 567.2 km/h

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All of the following have been associated with amount of cortisol within the body except __________. A. experiencing problems wi
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Read 2 more answers
The displacement of a wave traveling in the negative y-direction is D(y,t) = ( 4.60 cm ) sin ( 6.20 y+ 60.0 t ), where y is in m
trapecia [35]

Answer:

The question is incomplete, below is the complete question

"The displacement of a wave traveling in the negative y-direction is D(y,t) = ( 4.60cm ) sin ( 6.20 y+ 60.0 t ), where y is in m and t is in s.

A) What is the frequency of this wave?

B)  What is the wavelength of this wave?

C) What is the speed of this wave?"

Answers:

a.  f=\frac{30}{\pi }Hz\\

b. wavelength=\frac{\pi }{3.1}m \\

c. v=9.68m/s

Explanation:

The equation of a wave is represented as

D(x,t)=Asin(kx+wt) \\

Where A=amplitude

w=angular frequency=2πf

K=wave numbers =2π/λ

since we re giving he equation  D(y,t) = ( 4.60cm ) sin ( 6.20 y+ 60.0 t ),

we can compare and get the value for the wave number and angular frequency.

By comparing we have

w=60rads/s

k=6.20

a. to determine the frequency, from the expression fr angular wave frequency we have

w=2πf hence

f=w/2π

if we substitute we arrive at

f=\frac{60}{2\pi }\\f=\frac{30}{\pi }Hz\\

b. to determine the wave length, we use

k=\frac{2\pi }{wavelength} \\k=6.2\\wavelength=\frac{2\pi }{k} \\wavelength=\frac{2\pi }{6.2} \\wavelength=\frac{\pi }{3.1}m \\

c. the wave speed  v is express as the product of the frequency and the wavelength. Hence

v=frequency*wavelength \\v=\frac{30}{\pi } *\frac{\pi }{3.1}\\ v=9.68m/s

6 0
3 years ago
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