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RUDIKE [14]
3 years ago
7

The density of helium in a balloon is 1.18 g/L. If a

Chemistry
1 answer:
marissa [1.9K]3 years ago
3 0
There is 3.58 He in the balloon.
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They are located in Jerusalem.
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What is 1.23 x 10^-3 in standard notation
Andrew [12]

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=0.00123

Explanation:

Look at the attachments below

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Use the solubility curve above to answer the following: If I add 130 g of potassium iodide to 100 g of water at 10°C, how would
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7 0
3 years ago
If I have 7.5 L of a gas in a piston at a pressure of 1.75 atm and compress the gas until its volume is 3.7 L, what will the new
Sergio [31]

Answer:

3.55atm

Explanation:

We will apply Boyle's law formula in solving this problem.

P1V1 = P2V2

And with values given in the question

P1=initial pressure of gas = 1.75atm

V1=initial volume of gas =7.5L

P2=final pressure of gas inside new piston in atm

V2=final volume of gas = 3.7L

We need to find the final pressure

From the equation, P1V1 = P2V2,

We make P2 subject

P2 = (P1V1) / V2

P2 = (1.75×7.5)/3.7

P2=3.55atm

Therefore, the new pressure inside the piston is 3.55atm

7 0
3 years ago
Diatomic O2 can react with the element magnesium to form magnesium oxide (MgO). The balanced chemical equation is: 2Mg + O2 → 2M
tigry1 [53]

Answer:

We will expect 4 moles of MgO to be formed (option b).

Explanation:

Step 1: The balanced equation

2Mg + O2 → 2MgO

Step 2: Data given

Number of moles of Magnesium = 4 moles

Oxygen = in excess  → this means Magnesium is the limiting reactant

Magnesium will completely be consumed ( 4 moles). There will remain 0 moles.

For 2 moles of magnesium consumed, we need 1 mole of oxygen to produce 2 moles of MgO.

For 4 moles of magnesium, we need 4/2 = 2 moles of oxygen.

For 4  moles of magnesium, we will produce 4/1 = 4 moles of MgO

We will expect 4 moles of MgO to be formed (option b).

4 0
3 years ago
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