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Jlenok [28]
3 years ago
11

PLEASE HELP!!!

Chemistry
1 answer:
Romashka-Z-Leto [24]3 years ago
7 0

Answer:

43.76 g = 0.04376 Kg

Explanation:

The equation of the reaction is given as;

H2 + Cl2 --> 2HCl

From the equation;

1 mol of Cl2 produces 2 mol of HCl

Converting to mass;

Mass = Number of mol * Molar mass

Cl2;

Mass = 1 mol * 70.906 g/mol = 70.906 g

HCl;

Mass = 2 mol * 36.458 g/mol = 72.916 g

This means;

70.906 g of Cl2 produces 72.916 g of HCl

x g of Cl2 would produce 45g of HCl

70.906 = 72.916

x = 45

x = 45 * 70.906 / 72.916

x = 43.76g

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On combustion, 1.0 L of a gaseous compound of hydrogen, carbon, and sulfur gives 2.0 L of CO2, 3.0 L of H2O vapor, and 1.0 L of
Murrr4er [49]

Answer:

The empirical formula of the organic compound is  = C_2H_6S_1

Explanation:

At STP, 1 mole of gas occupies 22.4 L of volume.

Moles of CO_2 gas at STP occupying 2.0 L = n

n\times 22.4L=2.0L

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Moles of carbon in 0.08920 mol = 1 × 0.08920 mol = 0.08920 mol

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Moles of SO_2 gas at STP occupying 1.0 L = n''

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n''=\frac{1.0 L}{22.4 L}=0.04464 mol

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Moles of carbon in 0.08920 mol = 1 × 0.08920 mol = 0.08920 mol

Moles of hydrogen in 0.1339 moles of water vapor = 2 × 0.1339 mol = 0.2678 mol

Moles of sulfur in 0.04464 mol = 1 × 0.04464 mol = 0.04464 mol

For empirical; formula divide the least number of moles from all the moles of elements.

carbon = \frac{0.08920 mol}{0.04464 mol}=2

Hydrogen =  \frac{0.2678 mol}{0.04464 mol}=6

Sulfur = \frac{0.04464 mol}{0.04464 mol}=1

The empirical formula of the organic compound is  = C_2H_6S_1

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