1. Change in temperature
2. Odour being produced
3. Gas bubbles being formed
4. Solid precipitate is formed
5. Permanent change in colour
6. Light is being produced
Answer:

Explanation:
<u><em>1. First determine the empirical formula.</em></u>
a) Base: 100 g of compound
mass atomic mass number of moles
g g/mol mol
C 26.06 12.011 26.06/12.011 = 2.17
H 13.13 1.008 13.13/1.008 = 13.03
N 60.81 14.007 60.81/14.007 = 4.34
b) Divide every number of moles by the smallest number: 2.17
mass number of moles proportion
C 2.17/2.17 1
H 13.03/2.17 6
N 4.34/2.17 2
c) Empirical formula

d) Mass of the empirical formula

<u><em>2. Molecular formula</em></u>
Since the mass of one unit of the empirical formula is equal to the molar mass of the compound, the molecular formula is the same as the empirical formula:

The number of moles of nitrate dissolved in water if 6.15 mole of strontium nitrate is : 12.3 moles
<u>Given data :</u>
Moles of strontium nitrate = 6.15 moles
<h3>Ionization of Strontium Nitrate </h3>
When strontium nitrate (
) is placed in water it will dissociates into its ions because strontium nitrate is an ionic compound.
Next step : Represent the ionization of strontium nitrate

From the Stoichiometry of the chemical reaction
I mole of strontium nitrate = 2 moles of Nitrate ions
6.15 mole of strontium nitrate = 2 * 6.15
= 12.3 moles of Nitrate
Hence we can conclude that The number of moles of nitrate dissolved in water if 6.15 mole of strontium nitrate is : 12.3 moles.
Learn more about Stoichiometry of chemical reaction : brainly.com/question/27058367