Answer:
b. It deflects the electron to the right.
Explanation:
Since the sphere is positively charged and electron has negative charge, it will be attracted toward the sphere and hence,
The electron is deflected to the right as the positively charged sphere on its right
So, the 2nd option is correct.
Answer:
Most exceptions to the trend of decreasing radius moving to the right within a period occur in the d-block.
Explanation:
- In a period as we advance from left to right, the number of valence electrons in the same shell increases due to which the effective nuclear charge increases and thus the atomic size decreases.
- In d-block atomic radius initially decreases then remains constant and increases towards the end.
- As one moves from Sc (scandium) to Zn (zinc), the effective nuclear charge increases by a factor of 1, this is because:
- The number of electrons are low in the inner shell.
- The shielding power of d-orbital is low.
- Inter electronic repulsions will be operating at a value less than the nuclear charge, which will result in decrease in atomic radii.
- As the number of electrons in the inner orbital increases the outer electrons repel one another which enables them to push away.
- Although d-orbital has less shielding power, the number of electrons present in it are high. Hence, the electron-electron repulsive force becomes dominant, this results in an increase in the atomic radii.
Therefore, most exceptions to the trend of decreasing radius moving to the right within a period occur in the d-block.
Learn more about the periodic table here:
<u>brainly.com/question/9238898</u>
#SPJ4
Answer:
the formula for calculating acceleration is ending speed minus starting speed divided by time.
Answer:
No. Twice as much work will give the ball twice as much kinetic energy. But since KE is proportional to the speed squared, the speed will be 
times larger.
Explanation:
The work done on the ball is equal to the kinetic energy gained by the ball:
So when the work done doubles, the kinetic energy doubles as well:
However, the kinetic energy is given by
where
m is the mass of the ball
v is its speed
We see that the kinetic energy is proportional to the square of the speed, 
. We can rewrite the last equation as
which also means
If the work is doubled,
So the new speed is
So, the speed is 
times larger.
