To develop this problem we will apply the concepts related to the potential energy per unit volume for which we will obtain an energy density relationship that can be related to the electric field. From this formula it will be possible to find the electric field required in the problem. Our values are given as
The potential energy, 
The volume, 
The potential energy per unit volume is defined as the energy density.



The energy density related with electric field is given by

Here, the permitivity of the free space is

Therefore, rerranging to find the electric field strength we have,



Therefore the electric field is 2.21V/m
Right. You are true. The direction of the electric field is defined to be
the direction of the force on a small positive charge placed in the field.
Correct answer choice is :
B) Able to travel through a vacuum.
Explanation:
Electromagnetic waves are applied to carry long/short/FM wavelength radio waves, and TV/telephone/wireless signals or services. They are also effective for transferring energy in the form of microwaves, infrared radiation, visible light, ultraviolet light, X-rays, and gamma rays. Electromagnetic waves change from mechanical waves in that they do not need a medium to generate. This means that electromagnetic waves can move not only in the air and solid matters but also in the void of space.
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W = 1/2k*x^2.
k = spring constant = 2500 n/m.
x = distance = 4 cm = 0.04m (convert to same units).
W = 1/2(2500)(0.04)^2 = 2J.