La cantidad de azúcar en la solución es 239.4 gramos. En este caso, el azúcar es el soluto, y el agua el solvente.
El azúcar es el soluto el cual se encuentra disuelto en una solución acuosa que posee una masa de 6.3 kilogramos.
Un kilogramo equivale a 1,000 gramos. Es decir, 1 Kilogramo (kg) = 1,000 gramos (gr).
Entonces, la cantidad de azúcar puede ser calculada utilizando la regla de tres simple >>
6,300 gr ________ 100 %
X ______________ 3.8 %
X = (3.8 x 6,300)/ 100 = 239.4 gr
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The balanced chemical equation is:
<h3>2H₂SO₄ + Pb(OH)₄ —> Pb(SO₄)₂ + 4H₂O</h3>
Chemical equation can be balance by simply doing a head count of the different elements in the reactants and products to verified they are equal.
The equation given in the question above can be balanced as follow:
H₂SO₄ + Pb(OH)₄ —> Pb(SO₄)₂ + H₂O
There are 2 atoms of SO₄ on the right side and 1 atom on the left side. It can be balance by writing 2 before H₂SO₄ as shown below:
2H₂SO₄ + Pb(OH)₄ —> Pb(SO₄)₂ + H₂O
There are a total of 8 atoms of H on the left side and 2 atoms on the right side. It can be balance by writing 4 before H₂O as shown below:
2H₂SO₄ + Pb(OH)₄ —> Pb(SO₄)₂ + 4H₂O
Thus, the equation is balanced.
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m(O2)=50g
m(H2)=50g
m(H2O)-?
n2(H2)-?
2H2 + O2 = 2H2O
n(O2)= m (O2)/M(O2) =50g / 32 g/mol= 1,56 mol.
n(H2)= m (H2)/M(H2) =50g / 2 g/mol= 25 mol.
Since oxygen gas is the limiting reactant,
n(O2)< 2 n(H2) from reaction.
n(H2O)= 2n(O2)= 2n (H2 reac.)=2*1,56 mol=3,12mol.
m(H2O)=n(H2O)*M(H2O)= 3,12mol* 18 g/mol.
n2(H2)= n(H2) - n (H2 reac.)=25mol - 3,12mol=21,88mol.
K, ca, sc is the right answer. Take a look at table S of your chemistry reference table.