Would a meteorologist new to the local area have difficulty forecasting the weather?

What power output (in horsepower) of the engine of a 1.20 x 10^3 kg car if it can go from 25.0 km/hr to 100. km/hr in 12.0 s?

brilliants [131]

Answer:

48.5 hp

Explanation:

$m$ = mass of the car = 1200 kg

$v_{o}$ = initial speed of the car = 25 km/hr = 6.94 m/s

$v}$ = final speed of the car = 100 km/hr = 27.78 m/s

$t$ = time interval = 12 s

Power output of the engine is given as

$P = (0.5)\left ( \frac{m}{t} \right ) (v^{2} - v_{o}^{2})$

$P = (0.5)\left ( \frac{1200}{12} \right ) (27.78^{2} - 6.94^{2})$

$P = 36178.24$ W

we know that , 1 hp = 746 W

$P = \frac{36178.24}{746}$ hp

$P = 48.5$ hp

4 0

3 years ago

Two technicians are discussing fuse testing. Technician A says that a test light should light on both test points of the fuse if

Murljashka [212]

Answer:

C. Both technicians A and B

Explanation:

Both technicians are absolutely correct because a functional test light is meant to light on both test point if the fuse is working fine which implies that, if the test light doesn't light on both sides then there must be a fault with the fuse. So, both technicians A and B are very correct.

4 0

3 years ago

Shari uses the data in the table to predict how her weight on Venus would compare with her weight on Earth.

spin [16.1K]

Answer : <em>Her weight is lower on Venus because the acceleration due to gravity is lower.</em>

Explanation :

Venus is also called as Earth's twin. This is because both the mass and the size of Earth and Venus are almost same. The acceleration due to gravity on earth is $9.8\ m/s^2$ while on Venus is $8.87\ m/s^2$ .

So, when Shari measure her weight on Venus she found her weight is lower on Venus. This is because the acceleration due to gravity is lower on the surface of Venus as compared to the Earth.

Since, $w=mg$

i.e. weight depends on g.

<em>So, correct prediction is (b)</em>

3 0

3 years ago

Read 2 more answers

A parallel-plate capacitor has plates of area 0.40 m2 and plate separation of 0.20 mm. The capacitor is connected to a 9.0 V bat

mafiozo [28]

Answer:

a) E = 4.5*10⁴ V/m

b) C= 17.7 nF

c) Q = 159. 3 nC

Explanation:

a)

By definition, the electric field is the electrostatic force per unit charge, and since the potential difference between plates is just the work done by the field, divided by the charge, assuming a uniform electric field, if V is the potential difference between plates, and d is the separation between plates, the electric field can be expressed as follows:

$E = \frac{V}{d} = \frac{9.0V}{2*10-4m} =4.5 * 10e4 V/m (1)$

b)

For a parallel-plate capacitor, applying the definition of capacitance as the quotient between the charge on one of the plates and the potential difference between them, and assuming a uniform surface charge density σ, we get:

$Q = \sigma* A (2)$

From (1), we know that V = E*d, but at the same time, applying Gauss'

Law at a closed surface half within the plate, half outside it , it can be

showed than E= σ/ε₀, so finally we get:

$C = \frac{Q}{V} =\frac{\sigma*A}{E*d} = \frac{\sigma*A}{\frac{\sigma}{\epsilon_{o} } d} =\frac{\epsilon_{0}*A}{d} = \frac{8.85e-12F/m*0.4m2}{2e-4m} = 17.7 nF (3)$

c)

From (3) we can solve for Q as follows:

$Q = C* V = 17.7 nF * 9.0 V = 159.3 nC (4)$

6 0

3 years ago

What is the resistance of a 2 m long tungsten wire whose cross-sectional area of 0.15 mm2?

nadya68 [22]

The resistance of a 2 m long tungsten wire whose cross-sectional area of 0.15 mm² will be 0.74 ohm.

<h3>What is resistance?</h3>

Resistance is a type of opposition force due to which the flow of current is reduced in the material or wire. Resistance is the enemy of the flow of current.

ρ is the resistivity of tungsten = 5.6×10⁻⁸ (ohm m)

The relation of resistance with length and thickness is given by ;

$\rm R= \frac{\rho L}{A} \\\\ \rm R= \frac{5.6 \times 10^{-8}\times 2}{0.15 \times 10^{-6}} \\\\ R=0.74 \ ohm$

Hence, the resistance of tungsten wire will be 0.74 ohm.

To learn more about the resistance, refer to the link;

brainly.com/question/20708652

#SPJ1

3 0

2 years ago