It occurs when energy is supplied or withdrawn :)
The equatorial radius of the earth is
r = 6378 km = 6378 x 10³ m
The earth makes 1 revolution in 24 hours.
The angular velocity is
ω = (2π rad)/(24*3600 s) = 7.2722 x 10⁻⁵ rad/s
The tangential velocity (linear velocity) at a point on the equator is
v = rω
= (6378 x 10³ m)*(7.2722 x 10⁻⁵ rad/s)
= 463.8 m/s
Answer: 463.8 m/s
Answer:
So it will lift the mass by h = 17 m
Explanation:
As per energy conservation we know that
here we know that
now we have
so work done by the engine is 250 J
now we have
Answer:
v= - 4.507 i - 2.363 j
Explanation:
Given that
mc= 1490 kg
vc= 9.5 m/s ( - i)
mt= 1650 kg
vt = 6.4 m/s ( -j)
There is any external force so linear momentum will remain conserve.
Lets take final speed is v.
mc .vc + mt . vt = ( mc+mt) v
1490 x 9.5 ( - i) + 1650 x 6.4 ( -j) = ( 1490+1650) v
14,155 ( -i) + 10,560 ( - j) = 3140 v
v= - 4.507 i - 2.363 j
Answer:
a.
Explanation:
a
The property of air mass include
1) it must be large.
2) it must have relatively uniform properties.
3)it must travel as a recognizable entity.
It must have a warm front at its leading edge, is not necessarily a property of an air mass because Not all air masses have a warm front at their leading edge. There are five types of air masses and different types of the front can be developed.
