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4 years ago

The correctly balanced equation for H202 - H2O + O, is

Physics

1 answer:

Ne4ueva [31]4 years ago

5 0

Answer: The correctly balanced equation for H2O2 → H2O + O2 is A) H2O2 → 2H2O + O2 B)

Explanation:

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A -5.40nC point charge is on the x axis at x = 1.25m . A second point charge Q is on the x axis at -0.625m.

qwelly [4]

Answe

a) Q = 0.820 10⁻⁹ C , b) Q = -3.52 10⁻⁹ C

Explanation:

The electric field is given by the formula

E = k q / r²

where E is a vector quantity, so it must be added as a vector

E_total = E₁ + E₂

let's look for the two electric fields

E₁ = k q₁ / r₁²

E₁ = 9 10⁹ 5.4 10⁻⁹ / 1.25²

E₁ = 31.10 N / C

E2 = k Q / r₂²

E2 = 9 10⁹ Q / 0.625²

E2 = 23.04 10⁹ Q N / C (1)

now we can solve the two cases presented

a) The total field is

E_total = 50.0 N / C towards + x

since the test charge is positive the electric field E1 points to the right in the direction of the + x axis, so the equation is

E_total = E1 + E₂

E₂ = E_toal - E₁

E₂ = 50.0 -31.10

E2 = 18.9 N /C

With the value of the electric field we can calculate the charge (Q) using equation 1

E₂ = 23.04 10⁹ Q

Q = E₂ / 23.04 10⁹

Q = 18.9 / 23.04 10⁹

Q = 0.820 10⁻⁹ C

the charge on Q is positive

b) E_total = -50.0 N / C

E_total = E₁ + E₂

E₂ = E_total - E₁

E2 = -50.0 - 31.10

E2 = -81.10 N /C

we calculate the charge

Q = E2 / 23.04 10⁹

Q = -81.1 / 23.04 10⁹

Q = -3.52 10⁻⁹ C

for this case the charge is negative

5 0

3 years ago

What is characteristic of both sound waves andelectromagnetic waves?(1) They require a medium.(2) They transfer energy.(3) They

Amiraneli [1.4K]

The correct answer would be 2: they transfer energy.

3 0

3 years ago

Two fish swimming in a river have the following equations of motion:

IRINA_888 [86]

Answer:

The second fish, X2, is moving faster than the first fish, X1

Explanation:

The given parameters for the equation of motion of the fishes are;

X1 = -6.4 m + (-1.2 m/s)×t

X2 = 1.3 m + (-2.7 m/s)×t

The given equation are straight line equations in the slope and intercept form, where the slope is the speed and in m/s and the intercept is the starting point of swimming of the fishes

For the first fish, the intercept = -6.4 m, the slope = the speed = -1.2 m/s

For the second fish, the intercept = 1.3 m, the slope = the speed = -2.7 m/s

Whereby the fishes are swimming in the opposite direction of the measurement of length, we have;

The magnitude of the speed of the second fish $\left | -2.7 \ m/s \right | = 2.7 \ m/s$ , is larger than the magnitude of the speed of the first fish $\left | -1.2 \ m/s \right | = 1.2 \ m/s$

Therefore, the second fish, X2, is moving faster than the first fish, X1.

8 0

3 years ago

A grocery cart with a mass of 15 kg is pushed at constant speed along an aisle by a force fp = 12 n which acts at an angle of 17

Korolek [52]

Given:

Mass of cart: 15kg

Aisle length = 14m

Angle = 17° below the horizontal

Force fp = 12 N

So, the solution would be like this for this specific problem:

1) W(by applied force) = F(applied) x s x cosθ 
=>W(a) = 12 x 14 x cos17* = 160.66 J 

2) By F(net) = F(applied) - F(friction) 
=>As v = constant => a = 0 => F(net) = 0
=>F(applied) = F(friction)
=>W(friction) = -F(friction) x s
=>W(friction) = -F(applied) x s
=>W(f) = -12 x 14 x cos17* = -160.56 J 

3) 0, as the displacement is perpendicular to Force 

4) 0, as the displacement is perpendicular to Force

To add, the force that is applied to an object by a person or another object is called the applied force.

8 0

3 years ago

ANSWER ASAP

Stella [2.4K]

The weight of the plane is (mass) x (acceleration of gravity).
Neither of these changes when the plane rises from the ground.
Its weight on the ground is equal to (the same as) its weight in the air.

8 0

3 years ago

Read 2 more answers