Answer:
F = 15.47 N
Explanation:
Given that,
Q = 52 µC
q = 10 µC
d = 55 cm = 0.55 m
We need to find the magnitude of the electrostatic force on q. The formula for the electrostatic force is given by :
So, the magnitude of the electrostatic force is 15.47 N.
Answer:
Angle of diffraction for second order maxima is θ = 18.941°
Explanation:
From the question it is given that
wavelength of incident light = λ = 541 nm = 541 x
order of maxima = n =2
diffraction grating has 600 lines per mm
⇒ distance between two slit is = 1.66 x
m
using the relation of Braggs diffraction formula i.e.,
2dsinθ = nλ ..................................(1)
where, d = distance between two lines of grating
θ is the angle of diffraction
n= order of maxima
λ is the intensity of incident photon
on substituting the respected values in relation (1) we get,
2 x 1.66 x m sinθ = 2 x 541 x
⇒ sinθ = 0.3246
⇒ θ = = 18.941 °
As we can see here the lever has two forces at two ends
1. 300 N
2. 200 N
now we need to find the Torque on the lever about the fulcrum
so we will have
1. clockwise torque due to force at right end is
2. counterclockwise torque due to force at left end
so as per above calculations we can see that net torque on the lever is clockwise as it has more torque in clockwise direction
so <u>it will rotate clockwise</u>
Answer:
462 nm
Explanation:
Given: width of the slit, d = 5.6 × 10⁻⁴ m
Distance of the screen, D = 4.0 m
Fringe width, β = 3.3 mm = 3.3 × 10⁻³ m
First dark fringe means n =1
Wavelength of the light, λ = ?