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geniusboy [140]
3 years ago
10

If gravity on the moon is 1.62m/s, what is the weight of a 200g rock on the moon

Physics
1 answer:
igor_vitrenko [27]3 years ago
5 0
324 because when we use the formula for weight which is w=mg; W is weight; M is mass; G is gravity, now we multiply the gravity which is 1.62 m/s times the mass which is 200g and we will have 324. Hope it helps
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elena55 [62]

Answer:

W = 28226.88 N

Explanation:

Given,

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The radius of the planet, R = 4.38 x 10⁶ m

The time period of the satellite is given by the formula

                             T = 2\pi \sqrt{\frac{(R+h)^{3} }{R^{2} g} }  second

Squaring the terms and solving it for 'g'

                             g = 4 π² \frac{(R+h)^{3} }{R^{2}T^{2}  }   m/s²

Substituting the values in the above equation

                   g = 4 π² \frac{(4.38X10^6+4.13X10^5)^{3} }{(4.38X10^6)^{2}X6840^{2}}  

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Therefore, the weight

                                     w = m x g   newton

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                                         = 28226.88 N

Hence, the weight of the satellite at the surface, W = 28226.88 N                

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