Answer:
27.5 days
0.92 month
Explanation:
= radius of the orbit of moon around the earth =
= Mass of earth =
= Time period of moon's motion
According to Kepler's third law, Time period is related to radius of orbit as
inserting the values, we get
we know that
1 day = 24 hours = 24 x 3600 sec = 86400 s
1 month = 30 days
Answer:
A uniform meter rule of mass 100 g is balanced on a fulcrum at mark 40 cm by suspending an unknown mass m at the mark 20 cm. ... When the balancing mass is moved then the resultant moment is the difference of clockwise moment and anticlockwise moment.
Answer:
Explanation:
Assuming the crate does not lift above the ground and remains along the floor, then its acceleration will be in the horizontal direction. Therefore, we can use Newton's second law to find its acceleration:
where
is the net force on the crate along the x-direction
m is the mass of the crate
is the acceleration
Here we have:
m = 50.0 kg
is the component of the pulling force along the horizontal direction
Solving for the acceleration,
Answer:
Explanation:
First Question
This question has to do with the mass defect in AMU.
It would get closer to the actual answer if I knew what mass of proton you are using and the mass of one neutron as well.
<u>Formula</u>
- Am = Z*m_h + (A - Z)*m_n - M
- Am is the mass defect
- Z is the atomic number (number of protons). 29
- m_h is the accepted mass of a proton. 1.0078
- A = Atomic Mass number 63
- m_n = mass of the neutron 1.0087
- M is the actual mass of the atom in question. 62.92958
<u>Solution</u>
Am = 29*1.0078 + (63 - 29)*1.0087 - 62.92958
Am = 0.59242 u The difference between what I get and D is that I don't exactly know what m_h and m_n are.
Second Question
The first step is to calculate the mass defect. Just use the formula above.
<u>Givens</u>
- Am = ?
- Z = 7
- A = 14
- m_h = 1.0078
- m_n = 1.0087
- M = 14.00307
Solution
Am = 7*1.0078 + (14 - 7)*1.0087 - 14.00307
Am=0.11243 u
1 u = 931.5 MeV
0.11243 u = x
x = 104.7285
This is more of a reading problem than a physics problem. They want the energy per nucleon, which is 14 (neutrons and protons).
E = 104.7285/14
E = 7.5 MeV
Answer
A
B) and D)!!!!!!!!!!!!!!!!!!!!!!!!!!!!