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brilliants [131]
3 years ago
14

Suppose you increase your walking speed from 6 m/s to 13 m/s in a period of 1 s. What is your acceleration? m/s2

Physics
1 answer:
ziro4ka [17]3 years ago
5 0
Average acceleration is
Change in Velocity/change in time
So you could then do Vf-Vi/Tf-Ti
Which would look like 13m/s-6m/s / 1s-0s
Which then is 7m/s/1s which means the acceleration is 7m/s^2
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The atoms ,molecules,or compound present at the start of a chemical reaction that parcitipate in the reaction . which part of a
Tomtit [17]

Answer:

The atoms ,molecules, or compound present at the start of a chemical reaction that parcitipate in the reaction are <u><em>the reactants.</em></u>

Explanation:

The chemical reaction is the way in which one substance reacts against another. So, a chemical reaction consists of the transformation of some substances into others, that is, the process of arranging atoms and bonds when chemical substances come into contact.

In a chemical reaction, the initial substances are called reactants, while the new substances obtained are called products.

So, <u><em>the atoms ,molecules, or compound present at the start of a chemical reaction that parcitipate in the reaction are the reactants.</em></u>

8 0
3 years ago
What is hydraulic pressure?
Ilia_Sergeevich [38]
Hydraulic pressure is actually the pressure that is exerted to liquid and the pressure gets transmitted throughout the liquid. Since liquid cannot be compressed, so the pressure that was exerted on the liquid gets transmitted to the walls of the container containing the liquid. This theory is applied to the braking system of cars and some other vehicles. This is known as the hydraulic pressure. It is actually the science that is concerned with the laws of movements of a fluid  and the application of this theory for engineering purpose. This theory has not only been used in cars but also in planes .
3 0
3 years ago
Which type of experiment involves changing only one variable at a time
BlackZzzverrR [31]
Controlled Experiment 

6 0
3 years ago
Read 2 more answers
Use Newton's laws to explain why a falling object dropped from a 57m tower accelerates initially but then reaches constant veloc
snow_lady [41]

Answer:

At the point of dropping the object, by Newton's first law due to gravitational force F_g = m × g, accelerates

By Newton's Second law the object reaches impacts on the air with the gravitational force resulting in changing momentum of m×(Final Velocity - Initial Velocity)

As the velocity increases, the rate of change of momentum becomes equivalent to the gravitational force and by Newton's third law, the action action and reaction are equal and opposite hence they cancel each other out

The body then moves at a constant uniform motion down according to Newton's first law

Explanation:

At the point the object of mass, m, is dropped from the height of the tower, the only force acting on the object is the gravitational force such that the object has an acceleration which is the acceleration due to gravity, g, and the gravitational force is therefore = m × g

As the speed of the object increases while the object is falling with the gravitational acceleration the rate at which the object cuts through layers of air which (by Newton's first law of motion, are at rest ) has some buoyancy effect also increases therefore, the object is constantly increasingly changing the momentum of the air which by Newton's second law results, at an high enough velocity, and by Newton's third law, in a force equal to the applied gravitational force

Therefore, the force of the air drag becomes equal to the gravitational force, cancelling each other out and the object then moves according to Newton;s first law, in uniform motion of a constant speed while still falling down.

5 0
3 years ago
A light wave travels through air in equals 1.00 at an angle of 35 degrees what angle does it have when it passes from the air in
lyudmila [28]

Answer: Angle 59 degree

Explanation: Given that the

n1 = 1.0

n2 = 1.5

Øi = 35 degree

From Snell law, which says that

n1/n2 = sinØ1/ sinØ2

Substitute all the parameters into the formula

1/1.5 = sin 35/sinØ2

Cross multiply

Sin Ø2 = 1.5 sin35

SinØ2 = 1.5 × 0.573 = 0.860

Ø2 = sin^-1(0.860)

Ø2 = 59.36 degree

Ø2 = 59 degree ( approximately)

It has angle 59 degree when passing from air to glass

5 0
3 years ago
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