Answer:
![1.714\ \text{A}](https://tex.z-dn.net/?f=1.714%5C%20%5Ctext%7BA%7D)
Explanation:
F = Magnetic force = 0.018 N
B = Magnetic field = 0.03 T
L = Length of wire = 35 cm
= Angle between current and magnetic field = ![90^{\circ}](https://tex.z-dn.net/?f=90%5E%7B%5Ccirc%7D)
Magnetic force is given by
![F=IBL\sin\theta\\\Rightarrow I=\dfrac{F}{BL\sin\theta}\\\Rightarrow I=\dfrac{0.018}{0.03\times 35\times 10^{-2}\times \sin90^{\circ}}\\\Rightarrow I=1.714\ \text{A}](https://tex.z-dn.net/?f=F%3DIBL%5Csin%5Ctheta%5C%5C%5CRightarrow%20I%3D%5Cdfrac%7BF%7D%7BBL%5Csin%5Ctheta%7D%5C%5C%5CRightarrow%20I%3D%5Cdfrac%7B0.018%7D%7B0.03%5Ctimes%2035%5Ctimes%2010%5E%7B-2%7D%5Ctimes%20%5Csin90%5E%7B%5Ccirc%7D%7D%5C%5C%5CRightarrow%20I%3D1.714%5C%20%5Ctext%7BA%7D)
The magnitude of the current is
.
Answer:
40.91 m/s
Explanation:
w = angular velocity of the ball about the elbow joint = 30.3 rad/s
r = radius of circular turn = distance of the ball from the elbow joint = 1.35 m
v = linear velocity of the ball
Linear velocity of the ball is given as
v = r w
Inserting the values given above in the equation
v = (1.35) (30.3)
v = 40.91 m/s