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Ilya [14]
1 year ago
10

In part a, (a) why did you set the frequency of the square wave to 0.40 hz? (b) what would have happened if you had set the freq

uency much higher? much lower?
Physics
1 answer:
Tju [1.3M]1 year ago
7 0

If the frequency is much higher the capacitor will not get fully charged before the wave fall to zero states .here the time period is very low so the graph or output will look like this

If the frequency is much low => the time period is very high=>

After the first capacitor is fully charged, it stays in the same state (up to V). When the voltage reaches zero, the discharge begins. After being fully discharged, it stays in the same state until it reaches the next state because it has a very long time span.

Note that for all practical purposes the decay curve of the RC discharge circuit is exponential and the voltage across the capacitor plates is much less than 1% of the initial starting value after 5-time constants. please. Discharged.

Learn more about frequency here;

brainly.com/question/16148316

#SPJ4

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The Carson family's pancake recipe uses 2 teaspoons of baking powder for every 1/3 of a teaspoon of salt. How much baking powder
melomori [17]

Answer:

6 teaspoons of baking powder required.

Explanation:

Given that

According to the recipe of pancake,

For every \frac{1}{3} teaspoon of salt, 2 teaspoons of baking baking powder is required.

To find:

How much baking powder will be needed, if 1 teaspoon of salt was used ?

Solution:

This problem can be solved using ratio.

\frac{1}3 teaspoon of salt : 2 teaspoons of baking powder

Let us multiply the above ratio with 3.

\frac{1}{3}\times 3 teaspoon of salt : 2 \times 3 teaspoons of baking powder

OR

1 teaspoon of salt : 6 teaspoons of baking powder

So, answer is <em>6 teaspoons </em>of baking powder required.

Also, we can use the unitary method:

\frac{1}3 teaspoon of salt needs =  2 teaspoons of baking powder

1  teaspoon of salt needs =  \frac{2}{\frac{1}3} teaspoons of baking powder

1  teaspoon of salt needs = 2 \times 3 = <em>6</em>  teaspoons of baking powder needed

So, the answer is:

<em>6 teaspoons of baking powder </em>required.

5 0
3 years ago
Read 2 more answers
Emily sprains her ankle on her way home from school. Her mom suggests she use an “instant cold pack” to reduce the swelling. Whe
tresset_1 [31]
<span>In energy transfer, happens from one object to another without changing its form. For example, when you fill a pot of water and sit it on the stove, the water continues to heat until you turn it off. While in a energy transformation, the energy changes forms such as Chemical, kinetic.</span>
4 0
3 years ago
BRAINLIEST PLEASE HELP ASAP DO NOT ANSWER UNLESS YOU KNOW AND DON'T GIVE ME A LINK OR I WILL REPORT YOU
Korvikt [17]

Answer:

In a third class lever, the effort is located between the load and the fulcrum. ... If the fulcrum is closer to the effort, then the load will move a greater distance. A pair of tweezers, swinging a baseball bat or using your arm to lift something are examples of third class levers.

Explanation:

3 0
3 years ago
Archer shoots his arrow towards a target at a distance of 90 m and hits bullseye . Calculate the acceleration and time taken by
goldfiish [28.3K]

Answer:

acceleration = 45 m/s²

Time = 20 seconds

Explanation:

We are given;

Distance; s = 90m

Final velocity;v = 90 m/s

Since shot from rest, initial velocity;u = 0 m/s

So, to find the acceleration, we can use Newton's 2nd law of motion which is;

v² = u² + 2as

Where a is acceleration

Plugging in the values;

90² = 0² + 2a(90)

8100 = 180a

a = 8100/180

a = 45 m/s²

Now, for the time, we will use Newton's 1st law of motion which is;

v = u + at

Where t is time;

So;

90 = 0 + 4.5t

90 = 4.5t

t = 90/4.5

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3 0
3 years ago
Jim is driving his car at 32 m/s (72 mi/h) along a highway where the speed limit is 25 m/s (55 mi/h). A highway patrol car obser
Colt1911 [192]

Answer:

Given:

v1=32m/s,

v2=35m/s,

d1=250m,

d2=?

If both cars are travelling in the same direction, one at 32ms-1 and the other at 35 ms-1 then their relative velocity is Vr 3ms-1(by vector addition).

The time to catching Jim is t=d1/Vr= 250/3 = 83.3s

The distance traveled by the patrol car travel before catching Jim is d2 = v2t = v2 d1/Vr =35∙250/3= 2916.7m

Answer: d2= 2916.7m

Explanation:

4 0
3 years ago
Read 2 more answers
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