We are given with 98 Newton weight of an object on the surface of the earth with an acceleration equal to 9.8 m/s2. This means the mass of the object is equal to 98/9.8 or 10 kg. Hence the weight of the object 10,000 kilometers above sea level where acceleration is 1.49 m/s2 is 14.9 Newtons.
Answer:
The value of variable capacitor is
F
Explanation:
Given :
Inductance
H
Frequency
Hz
According to the cutoff frequency,

Now we find the value of capacitance,


F
Therefore, the value of variable capacitor is
F
Answer:
The frequency the listener hears is 911.765 Hz.
Explanation:
The speed of a sound is 340 m/s
The speed of listener is 30 m/s in a direction away from the whistle.
The speed of the listener with respect to the sound waves from the whistle
= ( 340 - 30) m/s
= 310 m/s
This because the direction of the sound waves from the whistle and the direction of travel of the listener are the same, that is, both are traveling away from the whistle.
Therefore from the formula we get
⇒
⇒
= 
The frequency the listener hears is 911.765 Hz.