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Ilya [14]
2 years ago
10

In part a, (a) why did you set the frequency of the square wave to 0.40 hz? (b) what would have happened if you had set the freq

uency much higher? much lower?
Physics
1 answer:
Tju [1.3M]2 years ago
7 0

If the frequency is much higher the capacitor will not get fully charged before the wave fall to zero states .here the time period is very low so the graph or output will look like this

If the frequency is much low => the time period is very high=>

After the first capacitor is fully charged, it stays in the same state (up to V). When the voltage reaches zero, the discharge begins. After being fully discharged, it stays in the same state until it reaches the next state because it has a very long time span.

Note that for all practical purposes the decay curve of the RC discharge circuit is exponential and the voltage across the capacitor plates is much less than 1% of the initial starting value after 5-time constants. please. Discharged.

Learn more about frequency here;

brainly.com/question/16148316

#SPJ4

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The inductor in the RLC tuning circuit of an AM radio has a value of 250 mHmH . You may want to review (Pages 857 - 860) . Part
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Answer:

The value of variable capacitor is 1.89 \times 10^{-13} F

Explanation:

Given :

Inductance L = 250 \times 10^{-3} H

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   f = \frac{1}{2\pi \sqrt{LC} }

Now we find the value of capacitance,

  C = \frac{1}{4\pi ^{2} f^{2}  L }

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  C = 1.89 \times 10^{-13} F

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3 years ago
The displacement of body is proportional to cube of time then body is uniform ​
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This doesn’t make sense
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Which type of reaction happens when a base is mixed with an acid?
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A whistle produces sound of frequency of 1.00 kHz. If a listener moves with a speed of 30 m/s away from the whistle, what freque
Serggg [28]

Answer:

The frequency the listener hears is 911.765 Hz.

Explanation:

The speed of a sound is 340 m/s

The speed of listener is 30 m/s in a direction away from the whistle.

The speed of the listener with respect to the sound waves from the whistle

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This because the direction of the sound waves from the whistle and the direction of travel of the listener are the same, that is, both are traveling away from the whistle.

Therefore from the formula we get

⇒     \frac{f_2}{f_1}  = \frac{v_2}{v_1}            ⇒  f_2 = 1000 \times \frac{310}{340}  = 911.765 \hspace{0.1cm} Hz

The frequency the listener hears is 911.765 Hz.

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3 years ago
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