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Ilya [14]
1 year ago
10

In part a, (a) why did you set the frequency of the square wave to 0.40 hz? (b) what would have happened if you had set the freq

uency much higher? much lower?
Physics
1 answer:
Tju [1.3M]1 year ago
7 0

If the frequency is much higher the capacitor will not get fully charged before the wave fall to zero states .here the time period is very low so the graph or output will look like this

If the frequency is much low => the time period is very high=>

After the first capacitor is fully charged, it stays in the same state (up to V). When the voltage reaches zero, the discharge begins. After being fully discharged, it stays in the same state until it reaches the next state because it has a very long time span.

Note that for all practical purposes the decay curve of the RC discharge circuit is exponential and the voltage across the capacitor plates is much less than 1% of the initial starting value after 5-time constants. please. Discharged.

Learn more about frequency here;

brainly.com/question/16148316

#SPJ4

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It's a bit of a trick question, had the same one on my homework. You're given an electric field strength (1*10^5 N/C for mine), a drag force (7.25*10^-11 N) and the critical info is that it's moving with constant velocity(the particle is in equilibrium/not accelerating). 
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<span>(7.25*10^-11 N) = (1*10^5 N/C)*Q1 ---> Q1 = 7.25*10^-16 C </span>
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