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Ilya [14]
1 year ago
10

In part a, (a) why did you set the frequency of the square wave to 0.40 hz? (b) what would have happened if you had set the freq

uency much higher? much lower?
Physics
1 answer:
Tju [1.3M]1 year ago
7 0

If the frequency is much higher the capacitor will not get fully charged before the wave fall to zero states .here the time period is very low so the graph or output will look like this

If the frequency is much low => the time period is very high=>

After the first capacitor is fully charged, it stays in the same state (up to V). When the voltage reaches zero, the discharge begins. After being fully discharged, it stays in the same state until it reaches the next state because it has a very long time span.

Note that for all practical purposes the decay curve of the RC discharge circuit is exponential and the voltage across the capacitor plates is much less than 1% of the initial starting value after 5-time constants. please. Discharged.

Learn more about frequency here;

brainly.com/question/16148316

#SPJ4

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An electron in the first energy level of the electron cloud has an electron in the third energy level
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Answer:

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Explanation:

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4 years ago
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Anna71 [15]

Answer:

371.2 mm

Explanation:

The Balmer series of spectral lines is obtained from the formula

1/λ = R(1/2² -1/n²) where λ = wavelength, R = Rydberg's constant = 1.097 × 10⁷ m⁻¹

when n = 15

1/λ = 1.097 × 10⁷ m⁻¹(1/2² -1/15²)

    = 1.097 × 10⁷ m⁻¹(1/4 -1/225)

    = 1.097 × 10⁷ m⁻¹(0.25 - 0.0044)

    = 1.097 × 10⁷ m⁻¹ 0.245556

    = 2.693 10⁶ m⁻¹

So,

λ  = 1/2.693 10⁶ m⁻¹

    = 0.3712 10⁻⁶ m

    = 371.2 mm

7 0
3 years ago
Please help on this one
PolarNik [594]

If the mass of both of the objects is doubled, then the force of gravity between them is quadrupled; and so on. Since gravitational force is inversely proportional to the square of the separation distance between the two interacting objects, more separation distance will result in weaker gravitational forces

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A heavy piece of hanging sculpture is suspended by a 90 cm-long, 5.0 g steel wire. When the wind blows hard, the wire hums at it
kupik [55]

Answer: The mass of the sculpture is 11.8kg

Explanation:

Using the equation of fundamental frequency of a taut string.

f = (1/2L)*√(T/μ) .... (Eqn1)

Where

f= frequency in Hertz =80Hz

T = Tension in the string = Mg

M represent the mass of the substance (sculpture) =?

g= 9.8m/s^2

L= Length of the string=90cm=0.9m

μ= mass density = mass of string /Length of string

mass of string =5g=0.005kg

L=0.9m

μ=0.005/0.9 = 0.0056kg/m

Using (Eqn1)

80= 1/(2*0.9) √(T/0.0056)

144= √(T/0.0056)

Square both sides

20736= T/0.0056

T= 116.12N

Recall that T =Mg

116.12= M * 9.8

M=116.12/9.8

M= 11.8kg

Therefore the mass of the sculpture is 11.8kg

4 0
3 years ago
what consistent physiological pattern are more common in women's teeth? A. Women's canines are generally sharper. B. Women have
irakobra [83]

Answer:

B

Explanation:

B. Women have straighter teeth.

5 0
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