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vodka [1.7K]
3 years ago
11

A bird lands on a bird feeder which is connected to a spring. The mass of the bird is exactly the same as the mass of the bird f

eeder. How does the added mass affect the period of oscillation of the bird feeder?
Physics
1 answer:
mihalych1998 [28]3 years ago
5 0

Answer:

The added mass will mean a longer period of oscillation.

Explanation:

The period of oscillation here is given by the formula;

T = 2π√(m/k)

Where m is mass and k is spring constant

From the equation of oscillation period above, it's obvious that when we increase the mass, the oscillation period will also increase.

Thus, the added mass will mean a longer period of oscillation.

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A closed system’s internal energy changes by 178 J as a result of being heated with 658 J of energy.
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Internal energy of the system changes by ΔE = 178 J.
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Via half-life equation we have:


A_{final}=A_{initial}(\frac{1}{2})^{\frac{t}{h} }


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4 years ago
A small branch is wedged under a 200 kg rock and rests on a smaller object. The small object that creates a pivot point is calle
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Answer:

F = 326.7 N

Explanation:

given data

mass m = 200 kg

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length L = 12 m

solution

we know force exerted by the weight of the rock that is

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W = 200 × 9.8

W = 1960 N

and

equilibrium the sum  of the moment about that is

∑Mf = F(cos∅) L - W (cos∅) d  = 0

here ∅ is very small so cos∅ L = L and cos∅ d = D

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solve it we get

F = 326.7 N

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Answer:

<u>Option-(A): </u>A new moon is quite near the Sun in the sky.

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