It would be the average I guess..300c temperature.Heat flows from higher temp. to lower temp. till the temp. of both the liquids are same.
Answer: A) see attach file .
B) the iamgen is uprigth
C) the imagen is virtual
Explanation: see attach file.
Answer:
The magnitude of force is 571.2 N.
Explanation:
Given data :-
i) Mass of the box = 84 kg.
ii) Frictionless surface means friction force is zero.
iii)The force ( F ) which act on box = m*a.
iv) The time for which the box is in motion ( t ) = 5 seconds.
v) The distance traveled by box ( S ) = 85 meter.
Now to find magnitude of force we have to calculate the value of acceleration.
We know the equation of motion.
S = (u*t )+0.5 (a*t²)
85 = 0 + 0.5 * a *5² ( u = initial velocity = 0 )
a = 6.8 m²/s.
∴ F = m*a = 84 * 6.8 = 571.2 N
Part A)
As we know see the graph
It travel from point A to G
so the displacement is from A to G directly
its 10 m towards North
Part B)
total distance we have to calculate total path length
so from A to B = 2 squares
from B to C = 4 squares
C to D = 1 square
D to E = 5 square
E to F = 1 square
F to G = 4 square
total distance = 2 + 4 + 1 + 5 + 1 + 4 = 17 square
1 square = 10 m
total distance = 170 m
PART C)
As we know that average speed is defined as

as we know that
total time = 45 s
total distance = 170 m
from above formula now

PART D)
As we know that average velocity is defined as

here we have
displacement = 10 m north
time = 45 s
now from above equation

Part E)
As we know that average acceleration is rate of change in the velocity
so here we have
final velocity = 3 m/s
initial velocity = 4 m/s
time = 3 s
now from the equation

