Help help help help help

Which of the following is the center of the universe according to the geocentric model?

Dima020 [189]

Earth is the center according to the geocentric model.

4 0

4 years ago

A wire 2.80 m in length carries a current of 5.20 A in a region where a uniform magnetic field has a magnitude of 0.430 T. Calcu

galina1969 [7]

Question:

A wire 2.80 m in length carries a current of 5.20 A in a region where a uniform magnetic field has a magnitude of 0.430 T. Calculate the magnitude of the magnetic force on the wire assuming the following angles between the magnetic field and the current.

(a)60 (b)90 (c)120

Answer:

(a)5.42 N (b)6.26 N (c)5.42 N

Explanation:

From the question

Length of wire (L) = 2.80 m

Current in wire (I) = 5.20 A

Magnetic field (B) = 0.430 T

Angle are different in each part.

The magnetic force is given by

$F=I \times B \times L \times sin(\theta)$

So from data

$F = 5.20 A \times 0.430 T \times 2.80 sin(\theta)\\\\F=6.2608 sin(\theta) N$

Now sub parts

(a)

$\theta=60^{o}\\\\Force = 6.2608 sin(60^{o}) N\\\\Force = 5.42 N$

(b)

$\theta=90^{o}\\\\Force = 6.2608 sin(90^{o}) N\\\\Force = 6.26 N$

(c)

$\theta=120^{o}\\\\Force = 6.2608 sin(120^{o}) N\\\\Force = 5.42 N$

3 0

3 years ago

a train travels some distance with a speed of 30km/h and returns with a speed of 45km/h. Calculate the average speed of the trai

Natali [406]

Answer:

let distance be D km

total time taken, T (hrs) = D/30 + D/50

Average speed , V = total distance/ total time = 2D/T = 2/(1/30+1/50) = 37.5 km/hr

Explanation:

7 0

3 years ago

Read 2 more answers

Calculate the pressure in a 212 liter tank containing 23.3 kg of argon gas at 25°c

NNADVOKAT [17]

First of all, let's find the number of moles of the gas.

The molar mass of argon is $M_m=40 g/mol=0.40 kg/mol$ . Since we have $m=23.3 kg$ of gas, the number of moles is
$n= \frac{m}{M_m}= \frac{23.3 kg}{0.40 kg/mol}=58.3 mol$

Now we can use the ideal gas law to calculate the pressure of the gas:
$pV=nRT$
where
p is the pressure
$V=212 L=0.212 m^3$ is the volume
$n=58.3 mol$ is the number of moles
$R=8.31 J/mol K$ is the gas constant
$T=25^{\circ}+273=298 K$ is the absolute temperature

Rearranging the equation, we find
$p= \frac{nRT}{V}= \frac{(58.3 mol)(8.31 J/mol K)(298 K)}{0.212 m^3}=6.81 \cdot 10^5 Pa$

7 0

4 years ago

All of the following activities produce quantitative data exept

Keith_Richards [23]

Answer:

The answer to your question are A and C

Explanation:

Quantitative data are quantities, something that we get after measuring something.

A. Measuring the rate of gas production from a chemical. This example is a quantitative measure, because we are measuring the rate.

B. Describing the clarity of water in a sample If we are describing something, means that we are not measuring anything, so this is not a quantitative measure.

C. Calculating the energy released from an electrochemical reaction If we are not measuring but we are using the data somebody else got to calculate energy, them this is a quantitative data.

7 0

3 years ago