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IgorC [24]
3 years ago
12

Look at the following math problem. 7 × 10 = 70 In this problem, you're multiplying 7 by 10. What is 10 called in this math prob

lem? Product Multiplicand Quotient Multiplier
Mathematics
1 answer:
umka2103 [35]3 years ago
3 0
For this case we have the following expression:
 7 × 10 = 70
 Where, by definition:
 7: multiplying
 10: multiplier
 By definition we have that the multiplier equals the number of times the multiplicand must be added.
 Therefore, 7 * 10 is to add 10 times 7:
 7 * 10 = 7 + 7 + 7 + 7 + 7 + 7 + 7 + 7 + 7 + 7 = 70
 Answer:
 
Multiplier
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Sindrei [870]

Answer:

100%

Step-by-step explanation:

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3 years ago
<img src="https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B-8%2F27%7D%20%3D%20-2%2F3" id="TexFormula1" title="\sqrt[3]{-8/27} = -2/3" al
sasho [114]
The equation is true because both sides are identical.
5 0
3 years ago
Find the domain of h(x)=x-3/x^3-36x
Dovator [93]

There is some ambiguity here which could be removed by using parentheses.  I'm going to assume that you actually meant:

               x-3

h(x) = ---------------

          (x^3-36x)

To determine the domain of this function, factor the denominator:

x^3 - 36x = x(x^2 - 36) = x(x-6)(x+6)

The given function h(x) is undefined when the denominator = 0, which happens at {-6, 0, 6}.

Thus, the domain is "the set of all real numbers not equal to -6, 0 or 6."

Symbolically, the domain is   (-infinity, -6) ∪ (-6, 0) ∪ (0, 6) ∪ (6, +infinity).

3 0
3 years ago
You are carpeting a room in a house for your job. You have a boss that likes to play jokes, so instead of just giving you the di
forsale [732]

Answer:

x^2-4x+3

63\ \text{sq. units}

Step-by-step explanation:

l = Length = \dfrac{x^2-x-6}{x-5}

w = Width = \dfrac{x^2-6x+5}{x+2}

Area is given by

A=lw\\\Rightarrow A=\dfrac{x^2-x-6}{x-5}\times\dfrac{x^2-6x+5}{x+2}\\\Rightarrow A=\dfrac{x^2-3x+2x-6}{x-5}\times\dfrac{x^2-5x-1x+5}{x+2}\\\Rightarrow A=\dfrac{(x-3)(x+2)}{x-5}\times\dfrac{(x-5)(x-1)}{x+2}\\\Rightarrow A=(x-3)(x-1)\\\Rightarrow A=x^2-4x+3

Area of the room is x^2-4x+3.

If x=10

Area of the room

A=x^2-4x+3=10^2-4\times 10+3\\\Rightarrow A=63\ \text{sq. units}

So, the amount of carpet needed would be 63\ \text{sq. units}.

4 0
3 years ago
Can you please explain and answer this question to me, (don't mind the blue dots, they are the answers of what I think, please l
Fofino [41]
I started with c, but you could’ve started with any box.

So I took the numbers in the c box (the black box in my picture) and divided to see which were multiples of two. They all were.

Then I went to a. All of a’s numbers were divisible by 7.

Then b. Two of them are divisible by 2, so that’s not the answer. None of them were divisible by 7, so there’s your answer!

Then d. Two are divisible by 7, so your rules is divisible by 2.

I hope this helps!

6 0
3 years ago
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