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meriva
3 years ago
11

Adding helium to a balloon increased its volume from 358.5 ml to 2.262 l. if the final number of moles of helium in the balloon

is 14.6 mol, what was the initial number of moles of helium in the balloon? assume the balloon contained only helium initially.
Chemistry
2 answers:
Alenkasestr [34]3 years ago
6 0

Answer : 2.31 moles of Helium was initially present in the balloon.


Explanation : Calculating the initial number of moles of helium in the balloon we need to use this method,

final moles present - 14.6 mol

Volume increased from 358.5 mL (= 0.3585 L ) to 2.26 L

<span>(14.6 mol) x (0.3585 L / 2.26 L) =  14.6 moles X 0.158 L = 2.31 moles / L</span>

<span>
</span>

<span>Hence, the initial moles was 2.31 moles/L in the helium balloon. </span>

Bezzdna [24]3 years ago
5 0

Answer:

0.08 mol

Explanation:

Easy clap too lazy to add an explanation but at least I'm not wrong.

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Write the complete balanced equation for the reaction between iron (III) oxide (Fe2O3) and water (H2O). You do not need to make
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Fe2O3+3H2O->2Fe(OH)3
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4 years ago
Assuming the reaction is first order in sucrose, determine the mass of sucrose that is hydrolyzed when 2.75 L of a 0.130 M sucro
Advocard [28]

Answer:125.84g

Explanation:Sucrose is dissacharides an organic compound in the class of carbonhydrate with the chemical formula C11H22O11.molar concentration is given by number of moles/Volume,this implies that moles=molar concentration ×Volume=0.130M×2.75L=0.3575moles.

Furthermore,number of moles=Mass of Sucrose/molecular Mass of Sucrose.

From it's formular C11H22O11, molecular Mass is the addition of the mass number which is 12 for C,2 for H and 16 for oxygen,O.so molecular Mass of Sucrose is (12×11)+(2×22)+(16×11)=352.

So mass =moles ×molecular mass=0.3575moles×352g/moles=125.84g

3 0
3 years ago
What is the condition of the outside air at a certain time and place?
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6 0
4 years ago
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Sodium metal reacts with water to produce hydrogen gas and sodium hydroxide according to the chemical equation shown below.
UNO [17]

<u>Answer:</u> The enthalpy change of the reaction is -361.6 kJ

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Moles of sodium = 0.025 moles

Molar mass of sodium = 23 g/mol

Putting values in above equation, we get:

0.025mol=\frac{\text{Mass of sodium}}{23g/mol}\\\\\text{Mass of sodium}=(0.025mol\times 23g/mol)=0.575g

We are given:

Mass of water = 100.00 g

Mass of sodium = 0.575 g

Mass of solution = 100.00 + 0.575 = 100.575 g

To calculate the amount of heat absorbed, we use the equation:

q=m\times C\times \Delta T

where,

q = amount of heat absorbed = ?

m = mass of solution = 100.575 g

C = specific heat capacity of solution = 4.18 J/g°C

\Delta T = change in temperature = (T_2-T_1)=(35.75-25.00)=10.75^oC

Putting all the values in above equation, we get:

q=100.575g\times 4.18J/g^oC\times 10.75^oC=4519.34J=4.52kJ

When heat is absorbed by the solution, this means that heat is getting released by the reaction.

<u>Sign convention of heat:</u>

When heat is absorbed, the sign of heat is taken to be positive and when heat is released, the sign of heat is taken to be negative.

For the given chemical reaction:

2Na(s)+2H_2O(l)\rightarrow NaOH(aq.)+H_2(g)

When 0.025 moles of sodium is reacted, the heat released by the reaction is 4.52 kJ

So, when 2 moles of sodium will react, the heat released by the reaction will be = \frac{4.52}{0.025}\times 2=361.6kJ

Hence, the enthalpy change of the reaction is -361.6 kJ

6 0
4 years ago
Chemistry help!!
Scrat [10]

The student originally has 252 grams of water in this experiment.

LAW OF CONSERVATION OF MASS:

  • The law of conservation of mass explains that matter (mass) can neither be created nor destroyed but can be changed from one form to another.

  • This means that in a chemical reaction, the sum of the masses of the reactants must equate to the total mass of product(s).

  • According to this question, a student conducts an experiment to separate water into hydrogen and oxygen. The student collects 28.0 g of hydrogen and 224.0 g of oxygen.

  • Since hydrogen and oxygen are the constituent elements of water, the sum of their masses must equate the mass of water.

  • Therefore, 224g of oxygen + 28g of hydrogen = 252g of water.

Learn more at: brainly.com/question/24996173?referrer=searchResults

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