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Stells [14]
2 years ago
10

Matching up of homologous pairs of chromosomes happens during

Chemistry
1 answer:
marin [14]2 years ago
5 0
Your correct answer is Synapsis
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The molecule NH3 contains all single bonds.<br><br> true <br> false
dsp73
<h3><u>Answer;</u></h3>

True

<h3><u>Explanation</u>;</h3>
  • The molecule NH3 contains all single bonds.
  • NH3 has a three single covalent  bond among its nitrogen and hydrogen atoms,because one valence electron of each of three atom of hydrogen is shared with three electron.
  • There are three covalent bonds are in NH3 . Each hydrogen make a single bond with nitrogen and there is also a pair of electron which is unpaired from nitrogen.
8 0
3 years ago
Read 2 more answers
Suggest the identity of the gas in the bubbles ​
Vlad1618 [11]

Answer:

<h3>it is hydrogen gas </h3>

3. the chemical equation is :

MgSO4 ( s ) + H2SO4 (aq)-->

MgSO4 (aq) + CO2 (g) + H2O (I)

THE IONISING OF H2SO4 IN SOLUTION IS CONPLEX

4. MAGNESIUM REACTION WITH DILUTE SULPHURIC ACID TO FORM

MAGNESIUM SULPHATE AND HYDROGEN GAS

Explanation:

hope it helps u

7 0
3 years ago
Read 2 more answers
Concentrated HCl is 15 M (15 molar). A 500 mL quantity of this solution is diluted by adding water to give a final volume of 2.5
Murrr4er [49]

The molarity of the resulting solution obtained by diluting the stock solution is 3 M

<h3>Data obtained from the question </h3>
  • Molarity of stock solution (M₁) = 15 M
  • Volume of stock solution (V₁) = 500 mL
  • Volume of diluted solution (V₂) = 2.5 L = 2.5 × 1000 = 2500 mL
  • Molarity of diluted solution (M₂) =?

<h3>How to determine the molarity of diluted solution </h3>

M₁V₁ = M₂V₂

15 × 500 = M₂ × 2500

7500 = M₂ × 2500

Divide both side by 2500

M₂ = 7500 / 2500

M₂ = 3 M

Thus, the volume of the resulting solution is 3 M

Learn more about dilution:

brainly.com/question/15022582

#SPJ1

7 0
2 years ago
If a solid has a density of 4g/cm^3 what volume of the solid has a mass of 24g? show work
ki77a [65]

Answer:

0.167cm^3

Explanation:

density=mass/volume

6 0
3 years ago
What is the mean free path for the molecules in an ideal gas when the pressure is 100 kPa and the temperature is 300 K given tha
sladkih [1.3K]

Answer:

The mean free path = 2.16*10^-6 m

Explanation:

<u>Given:</u>

Pressure of gas P = 100 kPa

Temperature T = 300 K

collision cross section, σ = 2.0*10^-20 m2

Boltzmann constant, k = 1.38*10^-23 J/K

<u>To determine:</u>

The mean free path, λ

<u>Calculation:</u>

The mean free path is related to the collision cross section by the following equation:

\lambda =\frac{1}{n\sigma }------(1)

where n = number density

n = \frac{P}{kT}-----(2)

Substituting for P, k and T in equation (2) gives:

n = \frac{100,000 Pa}{1.38*10^{-23} J/K*300K} =2.42*10^{25}\  m^{3}

Next, substituting for n and σ in equation (1) gives:

\lambda =\frac{1}{2.42*10^{25}m^{-3}* .0*10^{-20}m^{2}}=2.1*10^{-6}m

6 0
3 years ago
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