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timama [110]
3 years ago
15

For each of the following, highlight the element which has the highest:

Chemistry
1 answer:
Alex17521 [72]3 years ago
4 0
Atomic Radius: Br
Ionization Energy: Sc (not sure about this one, couldn’t find it in the periodic table)
Electronegativity: N

Reason: Found electronegativity and atomic radius in my periodic table, wasn’t sure about ionization energy, so i hope i guessed right
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In a soil profile, which is the second layer?<br> solid rock<br> subsoil<br> parent rock<br> topsoil
taurus [48]

Subsoil is the layer of soil under the topsoil on the surface of the ground.

7 0
3 years ago
How many grams of butane were in 1. 000 atm of gas at room temperature?
dimaraw [331]

The mass in grams of butane at standard room temperature is 53.21 grams.

<h3>How can we determine the mass of an organic substance at room temperature?</h3>

The gram of an organic substance at room temperature can be determined by using the ideal gas equation which can be expressed as:

PV = nRT

  • Pressure = 1.00 atm
  • Volume = 22.4 L
  • Rate = 0.0821 atm*L/mol*K
  • Temperature = 25° C = 298 k

1 × 22.4 L = n × (0.0821 atm*L/mol*K×  298 K)

n = 22.4/24.4658 moles

n = 0.91556 moles

Recall that:

  • number of moles = mass(in grams)/molar mass

mass of butane = 0.91556 moles × 58.12 g/mole

mass of butane = 53.21 grams

Learn more about calculating the mass of an organic substance here:

brainly.com/question/14686462

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3 0
2 years ago
How many H2O molecules are contained in 0.0016 moles of the hydrate Na2B4O7.10H2O?
mamaluj [8]
Maybe this example could help you to understand this problem.

https://image.slidesharecdn.com/121howmanyatoms-091201144624-phpapp02/95/12-1-how-many-atoms-17-728....
8 0
3 years ago
Read 2 more answers
16.
mixas84 [53]

Answer:

Explanation:

When going from top to bottom in any group of the periodic table, the atomic radius always tends to increase

8 0
3 years ago
How much heat is needed warm 65.34 g of water from 18.43 to 21.75
BaLLatris [955]

Given that  

Mass of water = 65.34 g

Amount of heat = mass of water * specific heat (temperature change

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= 65.34 g * 4.184 J / g-C ( 21.75-18.43 )C

= 907.63  J  

= 0.908 KJ

And  

1 cal = 4.186798 J

907.63 J * 1 cal / 4.186798 J =216.78  cal

Or0.218 kcal  


5 0
3 years ago
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