Sodium hydroxide and magnesium chloride react as shown by this equation: 2NaOH + MgCl2 → Mg(OH)2 + 2NaCl. Suppose the reaction b
1 answer:
Answer:- 25.2 g
Solution:- The balanced equation is:
From given balanced equation, there is 2:1 mol ratio between sodium hydroxide and magnesium hydroxide.
From given molarity and volume, we calculate the moles of NaOH and using mol ratio the moles of magnesium hydroxide are calculated that could easily be converted to grams on multiplying by it's molar mass.
Molar mass of = 24.305 + 2( 15.999 + 1.008)
= 24.305 + 2(17.007)
= 58.319 gram per mol
let's make the set up using dimensional analysis as:
=
So, 25.2 grams of magnesium hydroxide are formed.
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Answer:
Correc option:
Explanation:
size of atom : it says somthing about how many shell present in a particular atom or ion and it can also be evaluated on the basis of radius of atom.
Br^- and Kr has highest number of shell as compared to other group of species .
Na ,S , Mg ,P all are from 3rd period but Kr and Br^- in the 4th period so size of species of this group will more,
Size increases on increasring the shell number
Suppose we have 100 gr of the substance. Then by weight, it would contain 44.77 gr of C, 7.46 gr of H and 47.76 gr of S. We need to look up the atomic weights of these atoms; M_H=1, M_C=12, M_S=32. The following formula holds (where n are the moles of the substance, M its molecular mass and m its mass): n=m/M. Substituting the known quantities for each element, we get that the substance has 3.73 moles of C, 7.46 moles of H and 1.49 moles of S. In the empirical formula for the molecule, all atoms appear an integer amout of times. Hence, for every mole of Sulfur, we have 2.5 moles of C and 5 moles of H (by taking the moles ratios). Thus, for every 2 moles of sulfur, we have 5 moles of C and 10 moles of H. Now that all the coefficients are integer, we have arrived at an empirical formula for the skunk spray agent: 