Sodium hydroxide and magnesium chloride react as shown by this equation: 2NaOH + MgCl2 → Mg(OH)2 + 2NaCl. Suppose the reaction b
1 answer:
Answer:- 25.2 g
Solution:- The balanced equation is:
From given balanced equation, there is 2:1 mol ratio between sodium hydroxide and magnesium hydroxide.
From given molarity and volume, we calculate the moles of NaOH and using mol ratio the moles of magnesium hydroxide are calculated that could easily be converted to grams on multiplying by it's molar mass.
Molar mass of = 24.305 + 2( 15.999 + 1.008)
= 24.305 + 2(17.007)
= 58.319 gram per mol
let's make the set up using dimensional analysis as:
=
So, 25.2 grams of magnesium hydroxide are formed.
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Answer:
: 0.5 atm and
: 1 atm
Explanation:
In order to calculate the partial pressure for each gas , all you need to do is multiply the mole fraction of each gas with the total pressure.
It is given that = 1.5 atm
The mole fraction of each gas can be calculated in the following way:
= moles of
÷ total moles present =
= moles of
÷ total moles present =
Partial pressure of : 1.5 ×
= 0.5 atm
Partial pressure of : 1.5 ×
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Hope that answers the question, have a great day!