Answer:
the result for the following are (a) P is directly proportional to n
(b) V is directly proportional to T (c) P is directly proportional to T (d) T is inversly proportional to V (e) P is inversely proportional to V
We need to measure 20.0 grams of CaCl₂ to prepare 500 mL of 0.360 M solution.
First, we need to determine the required moles of CaCl₂. We have 500 mL (0.500 L) of a 0.360 M solution (0.360 moles of CaCl₂ per liter of solution).

Then, we will convert 0.180 moles to grams using the molar mass of CaCl₂ (110.98 g/mol).

To prepare the solution, we weigh 20.0 g of CaCl₂ and add it to a beaker with enough distilled water to dissolve it. We stir it, heat it if necessary, and when we have a solution, we transfer it to a 500 mL flask and complete it to the mark with distilled water.
We need to measure 20.0 grams of CaCl₂ to prepare 500 mL of 0.360 M solution.
You can learn more about solutions here: brainly.com/question/2412491
Answer: the pressure releases gas. The two most abundant gases are sulfur dioxide and carbon dioxide, and if levels of these gases increase,
Explanation:
Answer:
, the solution is basic
Explanation:
pH or pOH is the measure of acidity or alkalinity of a solution.
Acids have pH ranging from 1 to 6.9 and bases have pH ranging from 7.1 to 14.Neutral substances have pH of 7.
![pH=-\log [H_3O^+]](https://tex.z-dn.net/?f=pH%3D-%5Clog%20%5BH_3O%5E%2B%5D)
![pOH=-\log[OH^-]](https://tex.z-dn.net/?f=pOH%3D-%5Clog%5BOH%5E-%5D)
Putting in the values:
![pOH=-\log[5.5\times 10^{-5}]](https://tex.z-dn.net/?f=pOH%3D-%5Clog%5B5.5%5Ctimes%2010%5E%7B-5%7D%5D)



![9.8=-\log [H_3O^+]](https://tex.z-dn.net/?f=9.8%3D-%5Clog%20%5BH_3O%5E%2B%5D)
![[H_3O^+]=1.6\times 10^{-10}M](https://tex.z-dn.net/?f=%5BH_3O%5E%2B%5D%3D1.6%5Ctimes%2010%5E%7B-10%7DM)
As pH is more than 7, the solution is basic