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trapecia [35]
3 years ago
9

What is the total resistance in the circuit? (include unit in answer - ohms) I WILL GIVE BRAINLIEST!!

Physics
2 answers:
VashaNatasha [74]3 years ago
8 0
YES I TOOK THIS ! The answer is 25.79.
nadezda [96]3 years ago
3 0

Answer:

25.79

Explanation:

Give the person who answered before me BRAINLIEST, they deserve it.

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A block of mass 0.08 kg is pushed against a spring with spring constant k=31 N/m. The spring is compressed 0.15 meters from its
ELEN [110]

Answer:

1.11 meters

Explanation:

As the spring is compressed, elastic potential energy is built up in the spring. The total elastic potential energy can be found using the following formula

Ep = 1/2 x k x s²          

where k = 31 N/m  (spring constant)

s = 0.15 m  (compression)

Ep = 3.4875 J

When the block of mass is released, the elastic potential energy (Ep) is converted to kinetic energy (Ek). From this we can find the initial velocity of the mass of block after release

Ek = 1/2 x m x u²    

   

where Ek = Ep = 3.4875J

m = 0.08 kg  (mass of block)

u = unknown (initial velocity)

u = 2.9526 m/s

Now that we know the initial velocity we need to find the deceleration of the mass of block due to friction. We will first find the force of friction from the following formula

F = ∪ x m x g          

where F = unknown (frictional force)

∪ = 0.4   (coefficient of friction)

m = 0.08 kg   (mass of block)

g = 9.81 m/s² (acceleration due to gravity)

F = 0.31392 N

From this force we calculate the deceleration based on the following formula

F = m x a                  

where F = 0.31392   (frictional force)

m = 0.08 kg   (mass of block)

a = unknown  (acceleration)

a = -3.924 m/s²      -

*the negative sign is due to this value being deceleration

Now to find the total distance traveled we use the equation for motion

v² = u² + 2as            

where  v = 0 (final velocity)

u = 2.9526 m/s (initial velocity

a = -3.924 m/s² (deceleration due to friction)

s = unknown (distance traveled)

s = 1.11 meters

3 0
3 years ago
Two identical conducting small spheres are placed with their centers 0.290 m apart. One is given a charge of 12.0 nC and the oth
Solnce55 [7]

Answer:

Force between two identical conducting ball will be 2.65\times 10^{-5}N                        

Explanation:

We have given there is two identical conducting small spheres having charge q_1=12nC=12\times 10^{-9}C and q_2=-21nC=-21\times 10^{-9}C

Distance between centers of the ball is 0.290 m

So r = 0.290 m

We have to fond the electric force between the balls

According to Coulomb's law force between two charges is given by

F=\frac{1}{4\pi \epsilon _0}\frac{q_1_2}{r^2}=\frac{Kq_1q_2}{r^2}

So force F=\frac{9\times 10^{9}\times 12\times 10^{-9}\times 21\times 10^{-9}}{0.293^2}=2.65\times 10^{-5}N

So force between two identical conducting ball will be 2.65\times 10^{-5}N

4 0
3 years ago
How much force would it would be required to stop a 950kg car traveling at 30 M/S in 1.5 seconds
gavmur [86]

Answer:

28500

Explanation:

Force equation - F = m * a

F = 950 * 30

F = 28500

7 0
3 years ago
a measure has true value of 2.00and the measurement value was found to e 1.95.calculate the precision of the measuring instrumen
DiKsa [7]

The precision of the measuring instruments will be 2.5%.

<h3>What is precision?</h3>

It should be noted that precision simply means how close a test result will be when it's repeated.

In this case, the precision of the measuring instruments will be:

= (2 - 1.95)/2.

= 0.05/2

= 2.5%

Therefore, the the precision of the measuring instruments will be 2.5%.

Learn more about precision on:

brainly.com/question/5792909

8 0
2 years ago
Read 2 more answers
Two forces 6.0 N and 10.0 N act on an object at the same time.
sukhopar [10]

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

The Correct choice is ~

D. 18.0 Newtons

because the resultant force can't exceed 16 Newtons ~

6 0
3 years ago
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