To solve this problem we will apply the concepts related to the balance of forces. Said balance will be given between buoyancy force and weight, both described as derived from Newton's second law, are given as
Buoyancy force

Here,
V = Volume
=Density of air
g = Acceleration due to gravity
Weight

m = mass
g = Gravity
Our values are given as,




Then,

Replacing,

Now net force is ,

Mass of the sphere is

Now acceleration of the sphere is



Therefore the acceleration of the sphere as it falls through water is 
The angular frequency of the wave is determined as 75.4 rad/s.
<h3>
What is wave function?</h3>
A wave function is a mathematical equation for the motion of the wave.
y(x, t) = A sin(kx + ωt + Φ)
where;
- ω is angular speed
- k is angular wavenumber
- Φ is phase angle
<h3>What is angular frequency?</h3>
The angular frequency is the angular displacement of any wave element per unit of time or the rate of change of the waveform phase.
<h3>Angular frequency</h3>
ω = 2πf
ω = 2π(12)
ω = 75.4 rad/s
Thus, the angular frequency of the wave is determined as 75.4 rad/s.
Learn more about angular frequency here: brainly.com/question/3654452
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Answer: D
Explanation:
Atomic weight is measured by adding the number of protons and neutrons in an atom's nucleus. Argon's atomic number is 18 while potassium's is 19. This means that Argon will always have 18 protons while potassium will always have 19 protons.
To make the numbers easier to work with, round each atomic weight. We'll say the atomic weight of potassium is 39 and the atomic weight of argon is 40. To see how many neutrons each one has, I can set up a simple equation for each using the following equation:
Atomic weight = protons + neutrons
Potassium:
39 = 19 + N --> N = 20
Argon:
40 = 18 + N --> N = 22
An atom is defined by the number of protons it has, but the number of neutrons can vary. We call these isotopes, or atoms with the same number of protons but a different number of neutrons. As the math shows, argon typically has more neutrons per atom than potassium does.