Answer:
Energy stored at 12 volt will be 115.2 J and energy stored at 24 volt will be 460.8 volt
Explanation:
We have given capacitance of capacitor C = 1.6 F
Normal voltage V = 12 volt
And system uses 2 volt to charge the system
We know that energy stored in the capacitor is equal to 
So energy stored at 12 volt will be equal to 
And energy stored at 24 volt will be equal to 
So energy stored at 12 volt will be 115.2 j and energy stored at 24 volt will be 460.8 j
<span>Assume: neglect of the collar dimensions.
Ď_h=(P*r)/t=(5*125)/8=78.125 MPa ,Ď_a=Ď_h/2=39 MPa
τ=(S*Q)/(I*b)=(40*〖10〗^3*π(〖0.125〗^2-〖0.117〗^2 )*121*〖10〗^(-3))/(π/2 (〖0.125〗^4-〖0.117〗^4 )*8*〖10〗^(-3) )=41.277 MPa
@ Point K:
Ď_z=(+M*c)/I=(40*0.6*121*〖10〗^(-3))/(8.914*〖10〗^(-5) )=32.6 MPa
Using Mohr Circle:
Ď_max=(Ď_h+Ď_a)/2+âš(Ď„^2+((Ď_h-Ď_a)/2)^2 )
Ď_max=104.2 MPa, Ď„_max=45.62 MPa</span>
<span>A. The resistance has increased. Because here current is decreasing. Option C is incorrect cuz Power will decrease as resistance decreases according to equation P= v^2/R. V = volts, R = resistance. Hope it helps</span>
He is American. Alex Rodriguez
Answer:
As force = tension in string so tension in string is 400N
Explanation:
