The gravitational force between two asteroids is 6. 2 × 108 N. Asteroid Y has three times the mass of asteroid Z. If the distanc
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The velocity of B after elastic collision is 3.45m/s
This type of collision is an elastic collision and we can use a formula to solve this problem.
<h3>Elastic Collision</h3>The data given are;
- m1 = 281kg
- u1 = 2.82m/s
- m2 = 209kg
- u2 = -1.72m/s
- v1 = ?
Let's substitute the values into the equation.
From the calculation above, the final velocity of the car B after elastic collision is 3.45m/s.
Learn more about elastic collision here;
Answer:
1) A
2) C
3) B
4) A
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8) A
9) C
10) C
Explanation:
1) m = 15kg, a = , F = ma = 15*10 = 150N
2) m = 3kg, v = , r = 4m, F =
= 12N
3) a = , r = 10m, v=?
F = and F = ma
equating the two equations and cancelling a, we have:
= a
making v the subject of formula, we have:
v =
=
= 10
4) r = 10m, v = , a = ?
F =
F = ma
equating the above equations and making a subject of formula, we get:
a =
a = 25/10 = 2.5
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8) F =
assuming m and r is unity, that is the values are 1 respectively, the formula simplifies to:
F =
Now, if v is tripled
F =
F = 9
We can see that the force will be 9X greater than it was.
9) F =
assuming m and r is unity, that is the values are 1 respectively, the formula simplifies to:
F =
Now, if v is doubled
F =
F = 4
We can see that the force will be 4X greater than it was.
10) F =
assuming m and v is unity, that is the values are 1 respectively
F = 1/r
if r is doubled,
F = 1/2 * 1/r
We can see that the force is 1/2 as big as it was
Answer:
Da=(1/4)Db
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration due to gravity = 9.81 m/s²
When s = Da, t = t
When s = Db, t = 2t
Dividing the two equations
Hence, Da=(1/4)Db