<em>The answer is </em>Ninth <em>and </em>Tenth <em>grade so the answer would be</em> B
<em>I hope this helps you </em>
The variable you can change in an experiment is ( B ) A dependent variable
When we say directly northeast that is equivalent
to 45˚ north of east.
First let us determine the north and east
components of the acceleration using cos and sin functions:<span>
North = 2.18 * sin 45
East = 2.18 * cos 45
<span>Then we set to determine the east component of the plane’s
displacement by calculating using the formula:
d = vi * t + ½ * a * t^2
d = 135 * 18 + ½ * 2.18 * cos 45 * 18^2
<span>d = 2430 + 353.16 * cos 45 = 2679.72 m</span>
Calculating for the north component:
North = ½ * 2.18 * sin 45 * 18^2 </span></span>
North = 249.72 m
Hence magnitude is:
Magnitude = sqrt (2679.72^2 + 249.72^2)
Magnitude = 2,691. 33 m<span>
</span>
Calculating for angle:
Tan θ = North ÷ East <span>
<span>Tan θ = 249.72 m ÷ 2679.72 m</span></span>
θ = 5.32°<span>
</span>
So the plane was flying at 2,691. 33 m at 5.32<span>°</span>
Answer:
A. Workdone by helium, W = -1.829KJ
B. Internal energy, DE = 25.271KJ
Explanation:
Workdone can be defined as the force moving through a distance. For a gaseous system, when the volume of the gas expands, the system is losing energy. Therefore,
W = -P*DV
Where P is the pressure in pascal
DV is the change in volume in m3
DV = Vfinal - Vinitial
= 23.70 - 5.30
= 18.4L
W = -(0.981 * 18.4)
= -18.0504L.atm
Converting L.atm to joule,
= -18.0504 * 101.325
= -1828.97J
= -1.829KJ
If the system loses heat, Q the rection occurring is Exothermic.
Heat is the transfer of energy from one system to another.
Q = mcDT
Where m is the mass of the system
C is the specific heat capacity
Q = 27.20KJ
Internal energy is the summation of the heat supplied to a system and the workdone by the system
DE = Q + W
DE = 27.10 + (-1.829)
= 25.27KJ
