a cell wall, a large centralvacuole<span>, and </span>plastids<span> such as</span>chloroplasts<span>.</span>
N[Fe(NO₃)₃]=15.0 mol
n(O)=3×3×n[Fe(NO₃)₃]=9n[Fe(NO₃)₃]
n(O)=9×15.0=135.0 mol
Answer:
2.02 g H₂
General Formulas and Concepts:
<u>Chemistry - Atomic Structure</u>
- Reading a Periodic Table
- Using Dimensional Analysis
- STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K
Explanation:
<u>Step 1: Define</u>
22.4 L H₂ at STP
<u>Step 2: Identify Conversions</u>
STP - 22.4 L / mol
Molar Mass of H - 1.01 g/mol
Molar Mass of H₂ - 2(1.01) = 2.02 g/mol
<u />
<u>Step 3: Convert</u>
<u />
= 2.02 g H₂
Answer:
Gets exposed to oxygen (or water)
Explanation:
It's called oxidizing.
The given question is incomplete. The complete question is:
Calculate the number of moles and the mass of the solute in each of the following solution: 100.0 mL of 3.8 × 10−5 M NaCN, the minimum lethal concentration of sodium cyanide in blood serum
Answer: The number of moles and the mass of the solute are
and
respectively
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

where,
n = moles of solute
= volume of solution in ml


n = moles of
= 


Thus the number of moles and the mass of the solute are
and
respectively