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Eduardwww [97]
4 years ago
8

True or False ? Endothermic reactions are characterized by net absorption of thermal energy from its surroundings which leads to

an increase in temperature of the surroundings ?
Chemistry
1 answer:
Artemon [7]4 years ago
3 0
False

 Signed by Virtuoso
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What organelles are only found in plant cells
ZanzabumX [31]
 a cell wall, a large centralvacuole<span>, and </span>plastids<span> such as</span>chloroplasts<span>.</span>
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3 years ago
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How many moles of o are in 15.0 mol fe(no3)3?
krok68 [10]
N[Fe(NO₃)₃]=15.0 mol

n(O)=3×3×n[Fe(NO₃)₃]=9n[Fe(NO₃)₃]

n(O)=9×15.0=135.0 mol
7 0
4 years ago
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What is the mass of 22.4L of H2 at stp
bazaltina [42]

Answer:

2.02 g H₂

General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
  • STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K

Explanation:

<u>Step 1: Define</u>

22.4 L H₂ at STP

<u>Step 2: Identify Conversions</u>

STP - 22.4 L / mol

Molar Mass of H - 1.01 g/mol

Molar Mass of H₂ - 2(1.01) = 2.02 g/mol

<u />

<u>Step 3: Convert</u>

<u />22.4 \ L \ H_2(\frac{1 \ mol \ H_2}{22.4 \ L \ H_2} )(\frac{2.02 \ g \ H_2}{1 \ mol \ H_2} ) = 2.02 g H₂

5 0
3 years ago
Describe how iron turns into a brownish-red powder. Name the reactants and product that are involved.
IRISSAK [1]

Answer:

Gets exposed to oxygen (or water)

Explanation:

It's called oxidizing.

5 0
3 years ago
100.0 mL of 3.8M NaCN, the minimum lethal concentration of sodium cyanide in blood serum
9966 [12]

The given question is incomplete. The complete question is:

Calculate the number of moles and the mass of the solute in each of the following solution: 100.0 mL of 3.8 × 10−5 M NaCN, the minimum lethal concentration of sodium cyanide in blood serum

Answer: The number of moles and the mass of the solute are 0.38\times 10^{-5} and 18.62\times 10^{-5}g respectively

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n\times 1000}{V_s}

where,

n = moles of solute

V_s = volume of solution in ml

3.8\times 10^{-5}M=\frac{n\times 1000}{100.0}

n=0.38\times 10^{-5}

n = moles of NaCN = \frac{\text {given mass}}{\text {Molar mass}}

0.38\times 10^{-5}=\frac{x}{49g/mol}

x=18.62\times 10^{-5}g

Thus the number of moles and the mass of the solute are 0.38\times 10^{-5} and 18.62\times 10^{-5}g respectively

6 0
3 years ago
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