Answer:
1 mol Al; 1 mol O2
Explanation:ol Al; 10 mol O2
15.4 mol Al; 10.7 mol O2
or the reaction shown, find the limiting reactant for each of the initial quantities of reactants.
4Al(s) + 302(g) —> 2Al2O3(s)
Express your answer aor the reaction shown, find the limiting reactant for each of the initial quantities of reactants.
4Al(s) + 302(g) —> 2Al2O3(s)
Express your answer as a chemical formula.
1 mol Al; 1 mol O2
4 mol Al; 2.5 mol O2
12 mol Al; 10 mol O2
15.4 mol Al; 10.7 mol O2
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