The correct electronic configuration of vanadium 23 is
1s^22s^22p^63s^23p^64s^23d^3
This electronic configuration is correct because it obeys the Aufbau principle which state that electrons fill the atomic orbital of the lowest energy before occupying the higher level. S orbital can occupy a total of 2 electrons, p orbital can occupy a total of 6 electrons while d orbital can occupy a total of 10 electrons. in the electronic configuration above an s orbital is filled before p orbital while the p orbital is filled before the d orbital .
Answer: 272.5915639999...
Explanation:
1. slowly heat stubstance.
2. once the substance is at the most liqued state take the temp. that's the melting point of that subtance.
hope that helps, any other questions feel free to DM me dont wate your points. :)
