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gayaneshka [121]
2 years ago
15

A 0.00100 moles sample of ca(oh)2 requires 25.00 ml of aqueous hcl for neutralization. how many moles of acid are contained in t

he 25.00 ml?
a.0.0200
d.4.00 ´ 10–5
b.0.0400
e.none of the above
c.0.002
Chemistry
1 answer:
mr Goodwill [35]2 years ago
7 0
The balanced chemical equation for the reaction is as follows;
Ca(OH)2 + 2HCl —> CaCl2 + 2H2O
The stoichiometry of Ca(OH)2 to HCl is 1:2.
Number of Ca(OH)2 moles reacted = 0.00100 mol
Therefore number of HCl moles that should react with base is double the amount of moles of base reacted.
Number of acid moles in 25.00 ml
= 0.00100 mol x2 = 0.00200 mol
Correct answer is 0.002 mol
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Answer : The volume of carbon dioxide will be, 5.6122 L

Solution : Given,

Moles of LiOH = 0.5 moles

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Density of carbon dioxide = 0.00196 g/ml

First we have to calculate the mass of carbon dioxide.

The balanced reaction will be,

2LiOH+CO_2\rightarrow Li_2CO_3+H_2O

From the reaction we conclude that

As, 2 moles of LiOH absorbs 44 grams of carbon dioxide

So, 0.5 moles of LiOH absorbs \frac{0.5moles}{2moles}\times 44g=11 grams of carbon dioxide

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