Answer:
[∝] = +472
Explanation:
Specific rotation in a solution is defined as:
[∝] = ∝ / c×l
Where:
[∝] is specific rotation, ∝ is observed rotation (In degrees), c is concentration in g/mL and l is path length (In dm).
∝: +47.2°
c: 2.0g / 50mL = 0.04g/mL
l: 25cm × (1dm /10cm) = 2.5dm
Replacing:
[∝] = +47.2° / 0.04g/mL×2.5dm = <em>+472</em>
I hope it helps!
Answer is: volume of carbon dioxide is 1,84·10⁸ l.
Chemical reaction: C + O₂ → CO₂.
m(C) = 100 t · 1000 kg/t = 100000 kg
m(C) = 100000 kg · 1000 g/kg = 10⁸ g.
n(C) = m(C) ÷ M(C).
n(C) = 10⁸ g ÷ 12 g/mol.
n(C) = 8,33·10⁶ mol.
From chemical reaction: n(C) . n(CO₂) = 1 : 1.
n(CO₂) = 8,33·10⁶ mol.
m(CO₂) = 8,33·10⁶ mol · 44 g/mol.
m(CO₂) = 3,66·10⁸ = 3,66·10⁵ kg.
V(CO₂) = 3,66·10⁵ kg ÷ 1,98 kg/m³ = 1,84·10⁵ m³.
V(CO₂) = 1,84·10⁵ m³ · 1000 l/m³ = 1,84·10⁸ l.
The volume occupied by the gas in the container is 1 m³
Boyles law applies
P₁ V₁ = P₂ V₂
Where P₁ = 200kpa
P₂ = 300kpa
if its initial volume is 1.5
then,
P₁ V₁ = P₂ V₂
200 × 1.5 = 300 × V₂
V₂ = 200 × 1.5 / 300
= 1 m³
Hence the volume occupied by the gas container is 1 m³
Learn more about the Boyles law on
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Molecular Motion<span> is the speed at which molecules or atoms move dependent on temperature and state of matter.
Explanation:
</span>All molecules are<span> in constant motion. Molecules of a liquid have </span>a lot of<span> freedom of movement than those </span>in an exceedingly<span> solid. Molecules </span>in an exceedingly<span> gas have </span>the best<span> degree of motion.</span>
<span>
Heat, temperature </span>and also the<span> motion of molecules </span>area unit<span> all </span>connected<span>. Temperature </span>could be a life<span> of </span>the common K.E.<span> of the molecules </span>in an exceedingly<span> material. Heat </span>is that the<span> energy transferred between materials that have </span>completely different temperatures<span>. Increasing the temperature </span>will increase<span> the </span>travel<span> motion of molecules Energy </span>is expounded<span> to temperature by the relationship.</span>
