Please help me I need this now I'm from Phillippines it's science subject

Identify the power of ten that defines each of these prefixes. Input your answers as 10 x where x is the power of ten. nano- ___

Gemiola [76]

Answer: The quantity of every prefix is written below as a power of ten.

Explanation:

In the metric system of measurement, the name of multiples and subdivision of any unit is done by combining the name of the unit with the prefixes.

For Example: deka, hecto and kilo means 10, 100 and 1000 respectively. Deci, centi and milli means one-tenth, one-hundredth, and one-thousandth respectively.

The quantity of these prefixes are written as the power of 10.

For the given prefixes:

Nano: The quantity will be $10^{-9}$

Kilo: The quantity will be $10^3$

Centi: The quantity will be $10^{-2}$

Micro: The quantity will be $10^{-6}$

Milli: The quantity will be $10^{-3}$

Mega: The quantity will be $10^6$

Hence, the quantity of every prefix is written above as a power of ten.

7 0

4 years ago

A bowl of trail mix and a bowl of soup are examples of what type of matter?

BaLLatris [955]

I believe it would be compound.

5 0

4 years ago

Read 2 more answers

When you do physical exercise, the _____ energy stored in the carbohydrate, fat, and other molecules in the cells of your body i

Harman [31]

Potential energy is stored. As an item sits and does not move, potential energy builds up until said item moves, then it uses kinetic energy

6 0

3 years ago

Calculate the number of moles when 3.00l of a gas at 814 mmhg and 25 °c?

Mariulka [41]

Volume=V=3L
Pressure=P=814mmHg
Temp=T=25°C

So

No of moles=n

$\\ \rm\rightarrowtail PV=nRT$

$\\ \rm\rightarrowtail n=\dfrac{PV}{RT}$

$\\ \rm\rightarrowtail n=\dfrac{814(3)}{25R}$

$\\ \rm\rightarrowtail n=2442/25R$

$\\ \rm\rightarrowtail n=97.7Rmol$

5 0

2 years ago

The arsenic in a 1.223 g sample of a pesticide was converted to H3AsO4 by suitable treatment. The acid was then neutralized, and

Vladimir79 [104]

Answer:

5.471% As₂O₃ in the sample.

Explanation:

...the reaction is: Ag+ + SCN- => AgSCN(s) Calculate the percent As2O3 in the sample. (F.W. As2O3 = 197.84 g/mol).

First, with the amount of KSCN we can find the moles of Ag in the filtrates. As we know the amount of Ag added we can know the precipitate of Ag and the moles of AsO₄ = 1/2 moles of As₂O₃ in the sample:

Moles KSCN = Moles Ag⁺ in the filtrate:

0.01127L * (0.100mol / L)= 0.001127moles Ag⁺

Total moles Ag⁺:

0.0400L * (0.0781mol/L) = 0.0031564 moles Ag⁺

Moles of Ag⁺ in the precipitate:

0.0031564 - 0.001127 = 0.0020294 moles Ag⁺

Moles AsO₄ = Moles As:

0.0020294 moles Ag⁺ * (1mol As / 3 moles Ag⁺) = 6.765x10⁻⁴ moles AsO₄

Moles As₂O₃:

6.765x10⁻⁴ moles AsO₄ * (1 mol As₂O₃ / 2 mol AsO₄) =

3.382x10⁻⁴ moles As₂O₃

Mass As₂O₃:

3.382x10⁻⁴ moles As₂O₃ * (197.84g/mol) = 0.0669g As₂O₃

Percent is:

0.0669g As₂O₃ / 1.223g sample * 100 =

<h3>5.471% As₂O₃ in the sample</h3>

7 0

3 years ago

Please help me I need this now I'm from Phillippines it's science subject​

Please help me I need this now I'm from Phillippines it's science subject