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Maslowich
3 years ago
15

using the equation, C5H12 + 8O2 -> 5CO2 + 6H2O, if 108 g of water are produced, how many grams of oxygen were consumed?

Chemistry
1 answer:
vodomira [7]3 years ago
3 0
Molar mass:

H₂O = 18.0 g/mol

O₂ = 32.0 g/mol

<span>C</span>₅<span>H</span>₁₂<span> + 8 O</span>₂<span> -> 5 CO</span>₂<span> + 6 H</span>₂<span>O
</span>
8 x (32 g ) ------------ 6 x (18 g )
mass O₂ ------------ 108 g H₂O

mass O₂ = 108 x 8 x 32 / 6 x 18

mass O₂ = 27648 / 108

mass O₂ = 256 g

hope this helps!

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