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Maslowich
3 years ago
15

using the equation, C5H12 + 8O2 -> 5CO2 + 6H2O, if 108 g of water are produced, how many grams of oxygen were consumed?

Chemistry
1 answer:
vodomira [7]3 years ago
3 0
Molar mass:

H₂O = 18.0 g/mol

O₂ = 32.0 g/mol

<span>C</span>₅<span>H</span>₁₂<span> + 8 O</span>₂<span> -> 5 CO</span>₂<span> + 6 H</span>₂<span>O
</span>
8 x (32 g ) ------------ 6 x (18 g )
mass O₂ ------------ 108 g H₂O

mass O₂ = 108 x 8 x 32 / 6 x 18

mass O₂ = 27648 / 108

mass O₂ = 256 g

hope this helps!

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5.83 mol.

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The reamining moles of excess reactant "Al" = 8.1 mol - 2.27 mol = 5.83 mol.

6 0
3 years ago
Blank c2h4 + blank o2 → blank co2 + blank h2o how many moles of o2 are in the chemical equation when balanced using the lowest w
umka21 [38]

The reaction is<span>
C</span>₂H₄ + O₂ → CO₂ + H₂O<span>

To balance the equation, both side have same number of elements. Here,</span>

In left hand side has                                            in right hand side has

           4 H atoms                                                       2 H atoms 

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First, we have to balance number of C atoms and number of H atoms in both side.  
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After balancing the equation should be,</span>

C₂H₄<span> + 3O</span>₂<span> → 2CO</span>₂<span> + 2H</span>₂O


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