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Cloud [144]
3 years ago
7

Determine the relative amounts (in terms of volume fractions) for a 15 wt% sn-85 wt% pb alloy at 100°c. the densities of tin an

d lead at 100°c are given as follows: Ïsn = 7.29 g/cm3 Ïpb = 11.27 g/cm3
Chemistry
1 answer:
nikdorinn [45]3 years ago
6 0
Volume fraction = volume of the element / volume of the alloy

Volume = density * mass

Base: 100 grams of alloy

mass of tin = 15 grams

mass of lead = 85 grams

volume = mass / density

Volume of tin = 15g / 7.29 g/cm^3 = 2.06 cm^3

Volume of lead = 85 g / 11.27 g/cm^3 = 7.54 cm^3

Volume fraction of tin = 2.06 cm^3 / (2.06 cm^3 + 7.54 cm^3) = 0.215

Volume fraction of lead = 7.54 cm^3 / (2.06 cm^3 + 7.54 cm^3) = 0.785

As you can verify the sum of the two volume fractions equals 1: 0.215 + 0.785 = 1.000
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Answer:

See attached => LeChatelier's Principle

Explanation:

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Answers to worksheet (compare to attached notes)

1a. => increasing wt to product side => tilts right => shifts left

1b. => removing wt from reactant side => tilts right => shifts left,

1c. => increasing wt to product side => tilts right => shifts left

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3a. exothermic rxn => cooling => tilts left, rxn shifts right

3b. endothermic rxn => cooling => tilts right, rxn shifts left

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