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Cloud [144]
3 years ago
7

Determine the relative amounts (in terms of volume fractions) for a 15 wt% sn-85 wt% pb alloy at 100°c. the densities of tin an

d lead at 100°c are given as follows: Ïsn = 7.29 g/cm3 Ïpb = 11.27 g/cm3
Chemistry
1 answer:
nikdorinn [45]3 years ago
6 0
Volume fraction = volume of the element / volume of the alloy

Volume = density * mass

Base: 100 grams of alloy

mass of tin = 15 grams

mass of lead = 85 grams

volume = mass / density

Volume of tin = 15g / 7.29 g/cm^3 = 2.06 cm^3

Volume of lead = 85 g / 11.27 g/cm^3 = 7.54 cm^3

Volume fraction of tin = 2.06 cm^3 / (2.06 cm^3 + 7.54 cm^3) = 0.215

Volume fraction of lead = 7.54 cm^3 / (2.06 cm^3 + 7.54 cm^3) = 0.785

As you can verify the sum of the two volume fractions equals 1: 0.215 + 0.785 = 1.000
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Write an equation for the neutralization of lemon juice with baking soda. Your equation should show a proton transfer to form ca
Jobisdone [24]

The equation of the neutralization reaction is:

HOC(CO₂H)(CH₂CO₂H)₂ + Na₂CO₃ ----> HOC(CO₂Na)(CH₂CO₂Na)₂ + H₂O

<h3>What is the acid in lemon juice?</h3>

The main acid in lemon juice is citric acid.

Citric acid is a tricarboxylic acid and will react with baking soda to form a salt and water.

The equation of the neutralization reaction is shown below:

HOC(CO₂H)(CH₂CO₂H)₂ + Na₂CO₃ ----> HOC(CO₂Na)(CH₂CO₂Na)₂ + H₂O

In conclusion, the neutralization of citric acid in lemon juice produces a salt and water.

Learn more about neutralization reaction at: brainly.com/question/15042730
#SPJ1

8 0
2 years ago
the combustion of octane is given in this reaction 2C8H18+2502-----16CO2+18H2 O, identify the limit reagent for this reaction wi
Archy [21]

Answer:

Liming reagent in the given reaction is oxygen.

Explanation:

Mass of octane = 12.85 g

Mass of oxygen = 7.46 g

Molar mass of octane = 114.23 g/mol

Molar mass of oxygen = 32

Mole=\frac{Mass\;in\;g}{Molar\;mass}

No.\;of\;moles\;of\;octane=\frac{12.85}{114.23} = 0.1125\;mol

No.\;of\;moles\;of\;oxygen=\frac{7.46}{32} = 0.2331\;mol

2C_8H_{18} + 25O_2 \rightarrow 16CO_2 +18H_2O

According to the reaction, 2 moles of octane requires 25 moles of O2

so, 0.1125 moles of octane requires 0.1125\times \frac{25}{2}  = 1.40625\;mol of oxygen.

but only 0.2331 mol of oxygen is present.

Hence, oxygen is the limiting reagent

4 0
3 years ago
At what temperature will 0.654 moles of helium gas occupy 12.30 liters at 1.95 atmospheres?
DedPeter [7]

Answer:

447,25k

Explanation:

According to the ideal gas law

PV=nRT

Where:

P: is the pressure of the gas in atmospheres.

V: is the volume of the gas in liters.

n: number of moles of the gas

R: ideal gas constant

T: absolute temperature of the gas in kelvin

now using:

T=\frac{PV}{nR}\\ \\T=\frac{12,3L.1,95atm}{0,654mol.0,082(L.atm/K.mol)}\\ \\T=447,25K

3 0
3 years ago
What type of chemical bonding would exist between H-C-H?
Svetlanka [38]

Answer:

covalent bond

Explanation:

6 0
3 years ago
1. A sample of naproxen has 6.022x10^23 naproxen molecules. How many moles is this?​
11Alexandr11 [23.1K]

Answer:

0.99997661 moles

Explanation:

3 0
3 years ago
Read 2 more answers
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