Answer:
40 student 110 adult
this is using desmos
but to smash the equation you can go like basically we have to cancel out each variable to solve for the other
3x + 8y = 1000
x + y < =150
-3(x + y <= 150)
-3x -3y = -450
3x + 8y = 1000
5y = 550
y= 110
3x + 8 y = 1000
-8(x+y<=150) = -8x - 8y <= -1200
-5x = -200


x= 40
40 kids 110 adults
Answer:
Binomial
There is a 34.87% probability that you will encounter neither of the defective copies among the 10 you examine.
Step-by-step explanation:
For each copy of the document, there are only two possible outcomes. Either it is defective, or it is not. This means that we can solve this problem using the binomial probability distribution.
Binomial probability distribution:
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which
is the number of different combinatios of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.
In this problem
Of the 20 copies, 2 are defective, so
.
What is the probability that you will encounter neither of the defective copies among the 10 you examine?
This is P(X = 0) when
.


There is a 34.87% probability that you will encounter neither of the defective copies among the 10 you examine.
Answer:
d 21.94
Step-by-step explanation:
11.99×4.99+2.09+2.09+.78=21.94
Slope is rise over run which is -4/15
The length of ND = 3 units
The length of N'D' = 6
6 / 3 = 2
The scale factor is 2